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If 50 is passing: right now the contribution towards the total grade is (.70)*52, so the total grade = (.70)*52 + (.30)*E [for the final exam grade]. If the target is 50 for the total grade, then 50 = (.70)*52 + (.30)*E, and solve for E = (50 - (.70)*52)/(.30) = 45.3333, so a grade of 46 would put the final grade over 50. By the way, the maximum possible grade of a 100 on the final will result in 66.4 for the total grade.
Your grade would be 75 if you missed 25 questions out of 100. If there are 100 questions, each question would be worth one point.
To solve the equation "x/100 = 52," you would multiply both sides by 100 to isolate the variable x. This gives you x = 52 * 100, which simplifies to x = 5200. Therefore, the number that, when divided by 100, equals 52 is 5200.
Oh, dude, that's an easy one. So, like, you take 48 and you subtract it from 100. Math wizardry, right? The answer is 52. Boom. Math problem solved.
Solve algebraically. 52X = 100 X = 100/52 X = 25/13 ---------------- or 1.923076923