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Think about it. Say you have a square with sides 3. The perimeter is 4*3, or 12. Now multiple each side by 1/3. That's 1x4 or 4.

The ratio of before:after is 12:4, or 3:1. Thus, any multiplication/division change you make to the sides of a square will be paralleled in the perimeter.

Q: What happens to perimeter of square if sides are reduced to one third original length?

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What happens to the quick return ratio when the stroke length is reduced?

the perimeter will double. but the area should doubled to four

area = length x bredth new_area = (2 x length) x bredth = 2 x (length x bredth) = 2 x area → doubling the length, but leaving the bredth unchanged doubles the area. perimeter = 2 x (length + bredth) new_perinter = 2 x (2 x length + bredth) = 2 x (length + length + bredth) = 2 x length + 2 x (length + bredth) = 2 x length + perimeter → doubling the length, but leaving the bredth unchanged adds twice the original length (ie the new length of the rectange) to the perimter.

The length of a perimeter of 344 is, well, 344 . . .

The perimeter of a square is 400 meters. write an equation for the perimeter and solve for the length of one side

Related questions

Imagine an n-sided polygon with a side length of x, then perimeter = nx. If sides are reduced to x/2 the perimeter becomes nx/2, ie it is halved.

What happens to the quick return ratio when the stroke length is reduced?

the perimeter will double. but the area should doubled to four

5

The perimeter of a regular hexagon is: length times the # of sides, which in this case happens to be six. The perimeter of a regular hexagon= l(6)

The perimeter of a rectangle is given by (2L plus 2W). If you double either the width or length dimension, then it is four times the original dimension, such as (4L plus 2W) or (2L plus 4W).

Area is multiplied by 16. Perimeter is multiplied by 4.

As you double the length of all sides, the perimeter doubles.The area grows by (2 x 2) = 4 times.

area = length x bredth new_area = (2 x length) x bredth = 2 x (length x bredth) = 2 x area → doubling the length, but leaving the bredth unchanged doubles the area. perimeter = 2 x (length + bredth) new_perinter = 2 x (2 x length + bredth) = 2 x (length + length + bredth) = 2 x length + 2 x (length + bredth) = 2 x length + perimeter → doubling the length, but leaving the bredth unchanged adds twice the original length (ie the new length of the rectange) to the perimter.

Here's how to do that: 1). Find its length. 2). Find its perimeter. 3). Divide (its length) by (its perimeter). The quotient is the ratio of its length to its perimeter.

L is side length so perimeter is 4L. If L is tripled the perimeter becomes 4 x 3L = 12L, so perimeter is also tripled.

If the shape is a rectangle, then Perimeter = 2(Length + Width) So Width = Perimeter/2 - Length