area = length x bredth
new_area = (2 x length) x bredth
= 2 x (length x bredth)
= 2 x area
→ doubling the length, but leaving the bredth unchanged doubles the area.
perimeter = 2 x (length + bredth)
new_perinter = 2 x (2 x length + bredth)
= 2 x (length + length + bredth)
= 2 x length + 2 x (length + bredth)
= 2 x length + perimeter
→ doubling the length, but leaving the bredth unchanged adds twice the original length (ie the new length of the rectange) to the perimter.
the perimeter will double. but the area should doubled to four
Area = length*width new Area = 2 * length * width Area is doubled
if the length and breadth are increased by 5 times each area becomes 25 times
The minimum perimeter of a polyomino is the perimeter of the most square shape that can be formed. If the area can't form a perfect square, the minimum is formed by wrapping the additional units in a spiral around the smallest square or rectangle. Since 25 happens to be a perfect square (the square root is 5), the perimeter would be 2(5+5)=20. If the area were between 26 and 30 that would add two additional sides which would be 20+2. After 30 the units would wrap to a new side of the 5x6 arrangement (still a perimeter of 22) yielding a new perimeter of 22+2 or 24, which would persist until it exceeds 6x6, and so on.
Since the perimeter of a rectangle is 2 * length + 2 * width, 2l + 2w = 36 And since the length is twice the width, l = 2w Thus, you substitute 2w into the l in the first equation to get, 2(2w) + 2w = 36 4w + 2w = 36 6w = 36 w = 6 Plug the value of w into the second equation, l = 2(6) This will give you a length of 12. Since the area of rectangle is l * w, we just substitute the values in for length and width, l * w = 6 * 12 = 72 And that would be in square inches of course.
increase
the perimeter will double. but the area should doubled to four
It becomes a bigger rectangle - possibly a square.
If the altitude is not changed, the area would be doubled.
The perimeter also doubles.
Area = length*width new Area = 2 * length * width Area is doubled
Area is multiplied by 16. Perimeter is multiplied by 4.
It decreases. viz: perimeter of 5 x 5 square is 20 units, perimeter of 12.5 x 2 rectangle is 29 units...
When the linear dimensions of a plane figure are quadrupled, its perimeter is quadrupled, and its area is multiplied by 42 = 16 .
5
It would be 4 times greater.To find this algebraically: let L be the length and W the width originallyA = L x WWhen both are doubled, the equation becomesA = (2L) x (2W) = 4LWThe area of the rectangle is quadrupled if both the length and width are doubled.
If the length and width of a rectangle are multiplied by the same number, then . . . -- the perimeter is multiplied by the same number -- the area is multiplied by the square of the numbner