If the equation is y= x+2, then y will increase 1 when x increases 1
lets say x is 1 y will be 3
if x is 2, y will be 4
y=2x+5 y will increase 2 every time x increases by 1
x=1 y would be7
x=2 y would be 9
So the number that is multiplied by x is what determines the change in y, the numbers that are added or subtracted don't matter.
so y=7x y would change 7 every time x is changed 1
80x would mean that y changes 80 each time x changes by 1
The rule for a set of ordered pairs is the statement that states the relationship of of a certain value to another value.For example:given the set of ordered pair { (1,2) , (3,4) , (5,6) , (7,8) }we notice that the value of y is increased by 1 as the value of x varies.For instance, in the first ordered pair which is (1,2) where 1 is x and 2 is y such that (x,y), 1 increased by 1. In other words, x is increased by 1.So we say that the rule of the ordered pair is:{(x,y) | y = x + 1 }read as "The set of ordered pairs such that y is equal to x plus one"
It is: x+5 = 38 and the value of x is 35
The value of x is directly proportional to to the value of y.hence when the value of x increases the value of y decrteses and vice verse
The expression would be written as 16 The value of the expression is 1. 1 x 1 x 1 x 1 x 1 x 1 = 1
60 x 1.15 = 69
y is increased by 7
The rule for a set of ordered pairs is the statement that states the relationship of of a certain value to another value.For example:given the set of ordered pair { (1,2) , (3,4) , (5,6) , (7,8) }we notice that the value of y is increased by 1 as the value of x varies.For instance, in the first ordered pair which is (1,2) where 1 is x and 2 is y such that (x,y), 1 increased by 1. In other words, x is increased by 1.So we say that the rule of the ordered pair is:{(x,y) | y = x + 1 }read as "The set of ordered pairs such that y is equal to x plus one"
If the reflection is over the x value, the x-value does not change.
The magnification of the object will increase.
It means that for every '1' value of 'x', 'y' is increased by 0.159.
Using the quadratic formula, you will find for the equation 6x² + 2x + k = 0: x = (-b ±√(b² - 4ac)) / 2a → x = (-2 ± √(2² - 4×6×k)) / (2×6) → x = (-2 ± √(4 - 4×6k)) / (2×6) → x = (-1 ± √(1 - 6k)) / 6 The value of the discriminant (b² - 4ac) affects the value of x: >0 → there are two real values of x; this happens when 1 - 6k > 0 → k < 1/6; =0 → there is one repeated root, ie a single value of x; this happens when k = 1/6 (making x = -1/6); <0 → there are two complex values of x; this happens when k > 1/6.
The value of x is 7 because 7+5 = 12
It is: x+5 = 38 and the value of x is 35
let x be the number, then: (x + 1) × 2 + 5 = x + 1 → 2x + 2 + 5 = x + 1 → 2x + 7 = x + 1 → 2x - x = 1 - 7 → x = -6 The number is -6. Checking: -6 +1 = -5; 5 × 2 = -10; -10 + 5 = -5 which is the same as -6 + 1 = -5.
if value is 1 then its 1, all depends upon value of x
If: 5-3x = x+1 then the value of x = 1
x = -1