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Since the perimeter of a rectangle is 2 * length + 2 * width, 2l + 2w = 36 And since the length is twice the width, l = 2w Thus, you substitute 2w into the l in the first equation to get, 2(2w) + 2w = 36 4w + 2w = 36 6w = 36 w = 6 Plug the value of w into the second equation, l = 2(6) This will give you a length of 12. Since the area of rectangle is l * w, we just substitute the values in for length and width, l * w = 6 * 12 = 72 And that would be in square inches of course.

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Q: What happens when the perimeter of a rectangle is 36 inches if the length is twice the width what is the area in square inches of the rectanglr?

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