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If you want to know the area, then it will be, 1/2 X (12 + 8) X 6 = 60 sq.ft

Q: What if a trapazoid with bases of 12 ft and 8 ft and a height of 6?

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4 ft.

1 yd = 3 ft area = ½ × (sum bases) × height → area = ½ × (5 ft + 3½ yd) × 7 ft = ½ × (5 ft + (3½ × 3) ft) × 7 ft = ½ × (5 + 10½ ft) × 7 ft = 54¼ sq ft

A=0.5bhA=0.5*12*7A=42 ft2

12 ft

As the sun is far enough away, the rays of light are effectively parallel. This produces similar triangles with the ratio of sides the same in each case. As the shadow of the post is 12 ft and the shadow of the tree is 24 ft, the sides of the triangle of the tree are double that of the post. Assuming the post is parallel to the tree, the tree's height is twice the height of the post → tree = 12 ft × 2 = 24ft high.

Related questions

4 ft.

The area is 96 ft2

96 square feet.

Area = 0.5*base*height = 48 sq ft

1 yd = 3 ft area = ½ × (sum bases) × height → area = ½ × (5 ft + 3½ yd) × 7 ft = ½ × (5 ft + (3½ × 3) ft) × 7 ft = ½ × (5 + 10½ ft) × 7 ft = 54¼ sq ft

12 ft

A=0.5bhA=0.5*12*7A=42 ft2

12 ft

10-12 ft

78 feet squared.

base = 12 ft and height = 17 ft Check: 12*17 = 204 square feet Solved with the help of the quadratic equation formula.

Area = 0.5*base*height 27 = 0.5*12*height = 6*height So height = 27/6 = 4.5 feet.