Generally, when the median is greater than the mean it is because the distribution is skewed to the left. This results in outliers or values further below the median than above the median which results in a lower mean value than median value. When a distribution is skewed left, it is generally not very symmetrical or normally distributed.
If the distribution is not symmetric, the mean will be different from the median. A negatively skewed distribution will have a mean hat is smaller than the median, provided it is unimodal.
When the distribution has outliers. They will skew the mean but will not affect the median.
The median, by definition, tells you the "half way point" of your data. Exactly half of the observations in the dataset will be less than the median and half will be greater than the median.
The question is how do the mean and median affect the distribution shape. In a normal curve, the mean and median are both in the same point. ( as is the mode) If a distribution is skewed, its tail is either on the right or the left. If a distribution is skewed the median may be a better value to use than the mean since it has less effect on the shape. Also is there are large outliers, the median has less effect and is better to use. So the mean has a bigger effect on the shape many times than the median.
When a distribution is skewed to the right, the mean is greater than median.
Yes.
7,6,4,92,57,32
Generally, when the median is greater than the mean it is because the distribution is skewed to the left. This results in outliers or values further below the median than above the median which results in a lower mean value than median value. When a distribution is skewed left, it is generally not very symmetrical or normally distributed.
Yes, the median can be greater than the mean. It just depends on the values of the data. A simple series of 1,5,6 has 5 as the median, with a mean of 4.
In the same way that you calculate mean and median that are greater than the standard deviation!
true
As the mean is greater than the median it will be positively skewed (skewed to the right), and if the median is larger than the mean it will be negatively skewed (skewed to the left)
No because the mean is the highest numeral and the median is the middle numeral of the set of numbers so it is tecnictly impossible, but if you are using decimals, the median could get pretty close to the mean, but never higher.
I am guessing you are asking for an example of a set of numbers with these properties. Let's start with 5 numbers, so the median will be the middle number; say 1, 2, 3, 4, 5. The median is 3, but so is the mean. Now let's replace the 5 with 10. The median is still 3, but the mean is 4. To make the mode less than 3, let us change the 2 into a 1. Now the median is still 3, the mode is 1, and the mean is 3.8. So 1, 1, 3, 4, 10 will work.
One of the characteristics of mean when measuring central tendency is that when there are positively skewed distributions, the mean is always greater than the median. Another characteristic is that when there are negatively skewed distributions, the mean is always less than the median.
Whatever you like. The median value for each of the following three sets is 10. For the set {1, 9, 11, 12}. the mean is 8.25, smaller than the median. For the set {1, 9, 15, 15}. the mean is 10, the same as the median. For the set {1, 9, 15, 16}. the mean is 10.25, larger than the median.