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What in cm is the perimeter and area of a quadrilateral with vertices at -1 1 and -4 5 and 1 5 and 4 1?
Wiki User
∙ 6y ago
Drawing a sketch shows the quadrilateral to be a parallelogram.
Using one side parallel to x-axis as a base
→ area = length of base × distance between the parallel lines
= (4 -- 1) × (5 - 1)
= 5 × 4
= 20 square units.
For the perimeter you have two parallel sides of length (4 - - 1) = 5 units each
And two parallel side of length √((5 - 1)² + (-4 - -1)² = √(4² + 3²) = 5 units each
→ perimeter = 2 × 5 + 2 × 5 = 20 units
Now, if the grid is a centimetre grid, then these are 20 sq cm and 20 cm respectively.
If the grid is an inch grid, then 1 in = 2.54 cm
→ perimeter = 20 × 2.54 cm = 50.8 cm
→ area = 20 × 2.54² sq cm = 129.032 sq cm
For any other grid, you'll need to do the conversion yourself.
Wiki User
∙ 6y ago
Wiki User
∙ 6y agoPerimeter = 20 units of length.Area = 25 units of area.
Note that there is no reason for the coordinate grid to be defined in centimetres,
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