10X3 tens in unit form is written: 10*3 tens = 30 tens = 300 units.
10*6 = 6 tens and 0 units.
99 hundreds, 10 tens,4 ones
Nine tens = 90 Ten ones = 10 90 + 10 = 100
10 times six tens is 600 units which, in standard form, is 6*102.
It is 300.
10X3 tens in unit form is written: 10*3 tens = 30 tens = 300 units.
10*6 = 6 tens and 0 units.
99 hundreds, 10 tens,4 ones
To write 10 hundreds plus 10 tens plus 10 ones in standard form, you would add the respective values together. The value of 10 hundreds is 1000, the value of 10 tens is 100, and the value of 10 ones is 10. Adding these values gives us a total of 1110 in standard form.
Nine tens = 90 Ten ones = 10 90 + 10 = 100
10 times six tens is 600 units which, in standard form, is 6*102.
The general function is:1. y = a*x+bb is irrelevant and we can be removed2. y = a*xlets split x into ones and tens3. x = tens*10 + ones /e.g. 23 = 2*10 + 34. p1 = Multiplier of the onesp2 = Multiplier of the tens5. y = tens*10*p2 + ones*p1 /according to the question6. x*a = tens*10*p2 + ones*p1 /according to 2.7. (tens*10 + ones)*a = tens*10*p2 + ones*p1 /according to 3.8. tens*10*a + ones*a = tens*10*p2 + ones*p1 /regroup9. tens*10*a - tens*10*p2 + ones*a - ones*p1 = 0 /regroup10. tens*10*(a-p2) + ones*(a-p1) = 0 /regroup11. assuming "tens" and "ones" are not 0 then (a-p2) and (a-p1) must be 012. a-p2 = 0a-p1 = 013. a = p2a = p114. a = p1 = p2the answer is: when the Multipliers of ones and tens are equal then the product is called a.
To convert ones to tens, you need to divide by 10. In this case, 90 ones divided by 10 equals 9 tens. Each ten is equivalent to 10 ones, so 90 ones is equal to 9 tens.
To subtract 19 tens from 19 ones, we first need to convert both quantities to the same unit. Since there are 10 ones in a ten, we can rewrite 19 tens as 190 ones. Then, we subtract 19 ones from 190 ones, resulting in 171 ones. Therefore, the result of subtracting 19 tens from 19 ones is 171 ones.
There is no four digit number where the ones is twice the tens, the hundreds is five less than the ones, and the thousands is the sum of the tens and hundreds. int ones, tens, hundreds, thousands; for (thousands=1; thousands<10; thousands++) { /**/ for (hundreds=0; hundreds<10; hundreds++) { /**/ /**/ for (tens=0; tens<10; tens++) { /**/ /**/ /**/ for (ones=0; ones<10; ones++) { /**/ /**/ /**/ /**/ if (ones != 2 * tens) break; /**/ /**/ /**/ /**/ if (hundreds != ones - 5) break; /**/ /**/ /**/ /**/ if (thousands != tens + hundreds) break; /**/ /**/ /**/ /**/ printf ("dd\n", thousands, hundreds, tens, ones); /**/ /**/ /**/ } /**/ /**/ } /**/ } }
There are 8 tens in 80 ones. This is because in the base-10 number system, each group of 10 ones makes a unit of ten. Therefore, when you have 80 ones, you can divide it by 10 to find out how many tens there are, which in this case is 8.