To find 10 more than a given number y, you simply add 10 to y. This can be represented as y + 10. For example, if y = 5, then 10 more than y would be 5 + 10 = 15. So, the expression "10 more than y" can be simplified to y + 10.
y + 10
y < 10.
20 equals 8 more than a number y 20=y+8
Y + 11
Call your number 10x + y. x = y + 2 and 10x + y = 4 + 6(x + y) Substitute y + 2 for x: 10(y + 2) + y = 4 + 6((y + 2) + y) This simplifies to 10y + 20 + y = 4 + 6y + 12 + 6y, ie 20 - 16 = 12y - 11y so y = 4 and x = 6 Your number is 64, which is indeed 4 more than the sum of its digits.
x=y+10
y + 10
y < 10.
10 < y
y=88 88/2=44 44+10=54
Y + 7 = 7 more than y.
x=10; y=10; if (x >= 10 y >= 10) { //dostuff } OR: AND: && greater than: > greater than or equals to: >= less than: < less than or equal to: <= equals: NOT: !
x = 4z/5 y = .72z 5x/4 = z By subsitution, we have: .9x = y Thus, x is 10% more than y, and Without Loss of Generality, y is 10% less than x.
. . . . . . I know the answer but, I think this is the answer for me, I guess? . The correct answer is 10 + y. I guess? See ya laterrrr : l
If the tax rate is y (where y is less than 10%) then the answer is: 39.95 + (.0y times 39.95) If y = 9 then answer is 39.95 + (.09 x 39.95) = 39.95 + 3.60 = 43.55 (if the tax rate is 10% or more then its .10 or .11 or .12 etc)
Y - 12 < -10 Add 12 to both sides: Y < 2
20 equals 8 more than a number y 20=y+8