y + 10
y < 10.
Les than or equal to if x is no more than y than x < y
20 equals 8 more than a number y 20=y+8
10 more than 45 10 + 45 but the than means to switch45 + 10 = 55
x=y+10
y + 10
y < 10.
Y + 7 = 7 more than y.
x=10; y=10; if (x >= 10 y >= 10) { //dostuff } OR: AND: && greater than: > greater than or equals to: >= less than: < less than or equal to: <= equals: NOT: !
Les than or equal to if x is no more than y than x < y
20 equals 8 more than a number y 20=y+8
6y+1=19 6y=20 y=20/6=10/3~=3.333
. . . . . . I know the answer but, I think this is the answer for me, I guess? . The correct answer is 10 + y. I guess? See ya laterrrr : l
Y + 11
Call your number 10x + y. x = y + 2 and 10x + y = 4 + 6(x + y) Substitute y + 2 for x: 10(y + 2) + y = 4 + 6((y + 2) + y) This simplifies to 10y + 20 + y = 4 + 6y + 12 + 6y, ie 20 - 16 = 12y - 11y so y = 4 and x = 6 Your number is 64, which is indeed 4 more than the sum of its digits.
Suppose the numbers are x and y and that x < y Then y = 2x + 8 and x + y = 3y - 10 The second implies that x = 2y - 10 which, by the first gives x = 2(2x + 8) - 10 = 4x + 16 - 10 So -3x = 6 so that x = -2 and then y = 2*(-2)+8 = 4 So the two numbers are -2 and 4.