In 3n-1 equals 11, n is 4.3n - 1 = 113n - 1 + 1 = 11 + 13n = 123n/3 = 12/3n = 4
12n + 8 = 11 12n = 3 n = 1/4
5n + 3 = 14 - 6n <=> 5n +6n = 14 - 3 <=> 11n = 11 => n = 11/11 = 1
Let the integers be n and n + 1.n + 3(n+ 1) = 47 4n + 3 = 47 4n = 44 n = 11 n+ 1 = 12.
If you want to sum up numbers 1 to N, you can do it this way. Sum = (N+1)*(N/2).The reason this works: say you want to sum up 1 through 10. You have 10+1, 9+2, ..., 6+5. Each of these equals 11 [N+1]. You added 11 five times (N/2). Sum of 1 to 102 = (102+1)*(102/2) = 103*51 = 5253. You can check it by summing up the numbers with a spreadsheet.
In 3n-1 equals 11, n is 4.3n - 1 = 113n - 1 + 1 = 11 + 13n = 123n/3 = 12/3n = 4
1/100 or 0.01
-7
11
n = 1
12n + 8 = 11 12n = 3 n = 1/4
70 = 81-n subtract 70 from both sides 0 = 11 - n subtract 11 from both sides -11 = -n divide both sides by -1 11 = n
n - 8 = 11 Therefore, n = 11 + 8 n = 19
3*(n - 5) = 2*n + 11
When, in algebra, two letters are written next to each other as a term, such as m and n becoming mn, it means they are multiplied. So mn is a shorter way of writing "m times n" or "m x n"Therefore, when m = 1 and n = 1, mn = 1 x 1 = 1
n=1 is the the lowest level there is.
You have one linear equation in two unknown variables: A and n. There can be no solution.