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What is 11x15?

Updated: 4/28/2022
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9y ago

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11x15 is 165 thank you good luck!

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9y ago
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Q: What is 11x15?
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11 ft X 15 ft = 165 sq ft


What is square footage of 11x15?

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How many square yards of carpet will you need to cover a a floor that is 10 ft 6 inches by 14 feet 3 inches?

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What is the cost of Postage for a 8.5 X 11 envelope?

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How many feet will take to stop at 60 mph?

That depends on the deceleration applied, in which casetime = 2x45 mph/a = 90/awith a (the deceleration) measured in miles per hour per hour to give the time in hours.If you mean the time that would be taken using the stopping distances in the UK Highway Code, then, assuming a constant deceleration (from the moment the brakes are applied after the thinking distance):The stopping distance at 45 mph is 45 ft (thinking distance) + 101.25 ft (braking distance)[braking distance is speed2 / 20 ft = 452 / 20 ft = 101.25 ft]The thinking distance is travelled at 45 mph, giving:think_time = 45 ft / 45 mph= 45 ft /(45 x 5280 ft / 3600 seconds)= 45 x 3600 / (45 x 5280) seconds= 3600/5280 seconds= 15/22 seconds(This time is constant for all the emergency stopping distances given in the Highway Code.) Two equations of motion can be used to find the stopping time knowing the initial speed and distance (the final speed is zero):final_velocity2 = initial_velocity2 + 2 x acceleration x distancefinal_velocity = 0→ acceleration = - initial_velocity2 / (2 x distance)distance = initial_velocity x time + 1/2 x acceleration x time2→ distance = initial_velocity x time - (1/4 x initial_velocity2 / distance) x time2→ time2 - (4 x distance / initial_velocity) x time + 4 x distance2 / initial_velocity2 = 0→ (time - 2 x distance/initial_velocity)2 = 0→ breaking_time = 2 x distance / initial_velocity= 2 x (101.25 ft) / (45 x 5280 / 3600 ft per sec)= 202.5 x 3600 / (45 x 5280) seconds= 9x15/2x22→ total_stopping_time = 15/22 + 9x15/2x22 seconds= 11x15/2x22 seconds= 15/4 seconds= 33/4 seconds= 3.75 seconds.