answersLogoWhite

0

What is 11x15?

Updated: 10/14/2024
User Avatar

Wiki User

10y ago

Best Answer

Oh, dude, you're hitting me with some math, huh? Alright, so 11 times 15 is like, 165. It's like, you take 11 and add it to itself 15 times, and bam, you got your answer. Math, man, it's like magic but with numbers.

User Avatar

DudeBot

1mo ago
This answer is:
User Avatar
More answers
User Avatar

BobBot

1mo ago

Well, isn't that a happy little math problem! When you multiply 11 by 15, you get 165. Just imagine those numbers dancing together on the canvas of your mind, creating a beautiful masterpiece of mathematics. Remember, there are no mistakes in math, just happy little accidents.

This answer is:
User Avatar

User Avatar

ProfBot

1mo ago

11 multiplied by 15 is equal to 165. This can be calculated by adding 11 fifteen times or by using the distributive property of multiplication over addition, where 11 is multiplied by the sum of 10 and 5. In mathematical terms, 11 x 15 = 11 x (10 + 5) = (11 x 10) + (11 x 5) = 110 + 55 = 165.

This answer is:
User Avatar

User Avatar

Wiki User

10y ago

11x15 is 165 thank you good luck!

This answer is:
User Avatar

Add your answer:

Earn +20 pts
Q: What is 11x15?
Write your answer...
Submit
Still have questions?
magnify glass
imp
Continue Learning about Other Math
Related questions

How many square feet is 11x15?

11 ft X 15 ft = 165 sq ft


What is square footage of 11x15?

165 square feet


How many boxes of cake mix for a 11x15 sheet pan?

There are 11 cups of batter in an 11x15 pan for a 2 inch layer. I would guess for an 11x13, maybe 10 cups?


How many megapixels does the Kodak C330 have?

The Kodak model C330 camera takes 4 megapixel pictures. That is large enough to print 11x15 sized pictures. The camera also has an all-glass lens with a 3x optical zoom and 5x advanced digital zoom.


How do you bake a half sheet cake?

Poke some holes in it with a fork and wrap in foil bake at 300 degrees for 1 to 1 1/2 hours.In the microwave no foil and cook on high for 8 to 10 minutes.


What are the 15 times table?

15x1=15 15x2=30 15x3=45 15x4=60 15x5=75 15x6=90 15x7=105 15x8=120 15x9=135 15x10=150


How many square yards of carpet will you need to cover a a floor that is 10 ft 6 inches by 14 feet 3 inches?

I would recommend trying to find a 15 ft wide carpet that way you will have no seams. To figure out the yards you will need, round the measurements up to 11x15 and multiply those which give you 165. Take 165 divided by 9 = 18.333. So you need 19 yards. If your going to have seams and you have patterns this would not apply. You would have to figure out pattern repeat to figure out just how much you need.


What is the cost of Postage for a 8.5 X 11 envelope?

For specific information use theUSPS Link: http://www.usps.com/tools/calculatepostage/welcome.htm?from=global&page=0061calculatepostageIn general, you can mail any envelope up to 11x15 to qualify for first class postage, you then are charged by weight.In general, up to 8 sheets of 8.5x11 paper including envelope will require 2 stamps, 9-15 3 stamps.


How many feet will take to stop at 60 mph?

That depends on the deceleration applied, in which casetime = 2x45 mph/a = 90/awith a (the deceleration) measured in miles per hour per hour to give the time in hours.If you mean the time that would be taken using the stopping distances in the UK Highway Code, then, assuming a constant deceleration (from the moment the brakes are applied after the thinking distance):The stopping distance at 45 mph is 45 ft (thinking distance) + 101.25 ft (braking distance)[braking distance is speed2 / 20 ft = 452 / 20 ft = 101.25 ft]The thinking distance is travelled at 45 mph, giving:think_time = 45 ft / 45 mph= 45 ft /(45 x 5280 ft / 3600 seconds)= 45 x 3600 / (45 x 5280) seconds= 3600/5280 seconds= 15/22 seconds(This time is constant for all the emergency stopping distances given in the Highway Code.) Two equations of motion can be used to find the stopping time knowing the initial speed and distance (the final speed is zero):final_velocity2 = initial_velocity2 + 2 x acceleration x distancefinal_velocity = 0→ acceleration = - initial_velocity2 / (2 x distance)distance = initial_velocity x time + 1/2 x acceleration x time2→ distance = initial_velocity x time - (1/4 x initial_velocity2 / distance) x time2→ time2 - (4 x distance / initial_velocity) x time + 4 x distance2 / initial_velocity2 = 0→ (time - 2 x distance/initial_velocity)2 = 0→ breaking_time = 2 x distance / initial_velocity= 2 x (101.25 ft) / (45 x 5280 / 3600 ft per sec)= 202.5 x 3600 / (45 x 5280) seconds= 9x15/2x22→ total_stopping_time = 15/22 + 9x15/2x22 seconds= 11x15/2x22 seconds= 15/4 seconds= 33/4 seconds= 3.75 seconds.