The area of a parallelogram with a base of 20 inches and a height of 8.5 inches is 170 square inches.
Height = Area/Base = 105/15 = 7 inches
4 inches Area= 1/2(base)(height)
Area=(1/2)(base times height). This is written as A=bh/2. The base is 39 inches and the height is 15 inches, so: A=(39x15)/2=585/2=292.5 square inches
A rectangle and a triangle have equal areas. The length of the rectangle is 12 inches, and its width is 8 inches. If the base of the triangle is 32 inches, what is the length, in inches, of the altitude drawn to the base?
18 square inches is probably the area of the triangle, not the length of the base. The length of the base would be measured in inches (a unit of length), not square inches (a unit of area). So area = 1 / 2 * base * height = 18 square inches (given) height = 4 * base (given) 1 / 2 * base * 4 * base = 18 square inches 2 * base * base = 18 square inches base * base = 9 square inches base = 3 inches height = 4 * base = 4 * 3 inches = 12 inches Checking our work: height is 4 times the base (12 = 4 * 3) area is 18 (1/2 * 12 * 3).
The area of a parallelogram with a base of 9 inches and a height of 10 inches is 90 square inches.
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The area of a parallelogram with a base of 20 inches and an altitude of 8 inches is 160 square inches.
The hypotenuse of a right triangle with a base of 24 inches and height of 10 inches is: 26 inches.
The area of a parallelogram with a base of 20 inches and a height of 8.5 inches is 170 square inches.
A cone with a base radius of 4 inches and a height of 12 inches has a volume of 201.06 cubic inches.
The dimensions are: altitude 12 inches and base 7 inches Check: 0.5*12*7 = 42 square inches
Height = Area/Base = 105/15 = 7 inches
4 inches Area= 1/2(base)(height)
The area of the base is approximately 113.1 square inches.
The base is halved so, so too does the width need to be. 11/2 is 5.5 inches.