It is 12r - 20 or 4*(3r - 5)
-1
To answer a quadratic like this, st everything equal to zero. 5r^2+12r=-4r^2-4 9r^2+12r+4=0 Ask yourself what two numbers add to get 12 that multiply to get 9*4=36 1*36 no 2*18 no 3*12 no 4*9 no 6*6 yes (3r+2)(3r+2) The first and last multiply to get 6 and the outside and inside multiply to get 6. That's (3r+)^2
{5, 5, 8, 8, 12}{5, 5, 8, 8, 12}{5, 5, 8, 8, 12}{5, 5, 8, 8, 12}
8-3x-x = 12 8-4x = 12 -4x = 12-8 -4x = 4 x = -1
12r - 20
12r-20
It is 12r - 20 or 4*(3r - 5)
-6r-5 = 7-12r 12r-6r = 7+5 6r = 12 r = 2
- 6r - 5 = 7 - 12r add 12r to both sides 12r - 6r - 5 = 7 - 12r + 12r 6r - 5 = 7 add 5 to both sides 6r - 5 + 5 = 7 + 5 6r = 12 divide both side integers by 6 r = 2 ---------- check in original equation -6(2) - 5 = 7 - 12(2) - 12 - 5 = 7 - 24 - 17 = - 17 checks
12 Regular
Well, darling, the product of r and 12 is simply 12r. It's as easy as that, sweetie. So go ahead and use that little nugget of information however you please, honey.
12r + 4 = 112, 12r = 108, r = 9
r^2 - 12r + 27 what two factors of 27 add up to - 12? (r - 3)(r - 9) FOIL that and get the quadratic polynomial back
r - 12 ≥ 5r - 12 + 12 ≥ 5 + 12r ≥ 17
12r = p
12r - 15s - r + 3s = 11r -12s