13-11 = 2
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131 with 1 remaining 1,311 - 1 = 1,310 = 10 x 131
1 hour = 60 mins 1 min = 60 secs time = distance ÷ speed = 1 mile ÷ 6.5 mph = 2/13 hour = 2/13 x 60 mins = 93/13 mins = 9 mins 3/13 x 60 secs = 9 mins 1311/13 secs ≈ 9 mins 14 secs ≈ 9.25 mins
1 1 1 1 1 1 1 3 1 1 1 5 1 1 1 7 1 1 3 3 1 1 3 5 1 1 3 7 1 1 5 5 1 1 5 7 1 1 7 7 Note that in a combination, the order of the outcomes does not matter so that 1113 = 1131 = 1311 = 3111
To answer this question, you first need to find all the unique sets of 4 numbers that add up to 6. These are: 0006 0051 0042 0033 0411 0321 0222 3111 2211 Now we need to find which of these can be ordered to give numbers between 1111 and 9999: 0006: 6000 0051: 1500, 5001, 5010, 5100 0042: 2004, 2040, 2400, 4002, 4020, 4200 0033: 3003, 3030, 3300 0411: 1104, 1140, 1401, 1410, 4011, 4101, 4110 0321: 1203, 1230, 1302, 1320, 2013, 2031, 2103, 2130, 2301, 2310, 3012, 3021, 3102, 3120, 3201, 3210 0222: 2022, 2202, 2220 3111: 1113, 1131, 1311, 3111 2211: 1122, 1212, 1221, 2112, 2121, 2211 These are all the numbers between 1111 and 9999 with a digit sum of 6.
In military time, there are 24 hours in a day. To determine how many times the clock will display three or more of the same number in a row, we need to consider the possible patterns. There are four patterns where the clock will display three or more of the same number in a row: 00:00-00:02, 11:11-11:13, 22:22-22:24, and 33:33-23:35. Therefore, the clock will display three or more of the same number in a row four times over the course of one day using military time.