4 x 30 = 120 4 x 31 = 124 4 x 32 = 128 4 x 33 = 132 135 - 132 = 3 Answer: 33 with 3 remaining
135 millionths = 0.000135 = 1.35 x 10-4 in standard form.
135 = 1 x 135, 3 x 45, 5 x 27, 9 x 15,
1 x 135, 3 x 45, 5 x 27, 9 x 15, 15 x 9, 27 x 5, 45 x 3, 135 x 1
1 x 135, 3 x 45, 5 x 27, 9 x 15, 15 x 9, 27 x 5, 45 x 3, 135 x 1
The first ten positive integer multiples of 135 are: 1 x 135 = 135 2 x 135 = 270 3 x 135 = 405 4 x 135 = 540 5 x 135 = 675 6 x 135 = 810 7 x 135 = 945 8 x 135 = 1080 9 x 135 = 1215 10 x 135 = 1350
3 x 3 x 3 x 5 = 135
The first is 135 next is 135x2=270 then 135x3=405 then 135 x 4
540
135 = 3 x 3 x 3 x 5
4 x 30 = 120 4 x 31 = 124 4 x 32 = 128 4 x 33 = 132 135 - 132 = 3 Answer: 33 with 3 remaining
20% of 135 pounds is (20/100) x 135 = (1/5) x 135 = 27 So 135 pounds minus 20% discount = 135 - 27 = 108 Another way of looking at this is that after a discount of 20% the object really costs only 80% of the original price, hence 135 pounds minus 20% discount = 80% of 135 = (80/100) x 135 = (8/10) x 135 which is equal to (4/5) x 135 = 4 x 27 = 108
The prime factors of 135 are 3, 3, 3, 5 3x3x3x5 = 135 You could, of course also multiply together -3 x -3 x 3 x 5 = 135 or -3 x 3 x 3 x -5 = 135 or -3 x -3 x -3 x -5 = 135
For any two counting numbers x and y:LCM(x, y) x HCF(x, y) = Product of x and yLCM(x, y) = (Product of x and y)/HCF(x, y)Here, we have 108 and 135 & their product = 108 x 135But, HCF(108, 135) = ?So, we shall first calculate HCF by the method of prime factorization.108 = 33x22 & 135 = 33x51It is clear that 33 is the HCF of 108 and 135.So, LCM(108, 135) = (108 x 135)/33 = 4 x 135 = 540
1353 = 135 x 135 x 135 = 2460375
255
135