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Assuming a period of 13 years has four leap years, then the number of seconds in thirteen years is equal to (60 x 60 x 24 x 365 x 9) + (60 x 60 x 24 x 366 x 4) = 410313600 seconds. If a period of 13 years has three leap years, then the number of seconds in thirteen years is equal to (60 x 60 x 24 x 365 x 10) + (60 x 60 x 24 x 366 x 3) = 410227200 seconds.
In a 50 year spell which includes 12 leap years, there are a total of (365 x 24 x 60 x 60 x 38) + (366 x 24 x 60 x 60 x 12) = 1577836800 seconds in 50 years. In a 50 year spell which includes 13 leap years, there are a total of (365 x 24 x 60 x 60 x 37) + (366 x 24 x 60 x 60 x 13) = 1577923200 seconds in 50 years.
Multiply the number of days by 86400 (that is, 24 x 60 x 60).
Let the number be x and so if 13-x = 73 then x = -60 because 13-(-60) = 73
13 x 60 = 780 minutes 780 x 60 = 46800 seconds