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What is 13x4?

Updated: 4/28/2022
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14y ago

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13x4=52

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Q: What is 13x4?
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Related questions

What is the square feet for 13X4?

4.76


What is 13 over 52 reduced?

13/52=1/4 since 13x4=52


What is four fifths of 65?

4/5 of 65 is 52 because 65 divided by 5 is 13 and 13x4=52 and the rule is divide by the bottom and times by the top.


Can you make 52 using 2 4 5 and 9 in any combination only once?

yes. 9x2-5x4 = 52 9x2 = 18 18-5 = 13 13x4 = 52


What is 13 times 4?

It's 52. :)13x4=52


What does 13 times -4 equal?

17


What is 6 and a holf multiplied by 4 5ths?

The first step in answering this is to change the mixed number into a vulgar fraction. This can be done by multiplying the units by the denominator and then adding this to the numerator. In this case, we have 6x2+1 = 13, and so 6 1/2 can be rewritten as 13/2. The next thing to note is that when multiplying fractions, you multiply both the numerators and the denominators. So in this case you do 13x4 = 52 and 2x5 = 10. Therefore the answer is 52/10. This can be converted to the mixed number 5 1/5


How many cards in a deck including jokers?

There are 52 cards in a standard deck and, if there are only 2 jokers, any genius will be able to work out that there are 54 cards in total.


What is the four times table?

the four times table is incredibly easy! ill tell you them up to 26 1x4=4 2x4=8 3x4=12 4x4=16 5x4=20 6x4=24 7x4=28 8x4=32 9x4=36 10x4=40 11x4=44 12x4=48 13x4=52 14x4=56 15x4=60 16x4=64 17x4=68 18x4=72 19x4=76 20x4=80 21x4=84 22x4=88 23x4=92 24x4=96 25x4=100 26x4=104 i could go on and on. hope this helps!


Why are there fifty two cards in a normal pack?

There are 4 suits and each suit has 13 cards. 4 x 13 = 52. Fun With Math: Pick a card, any card. Say it's a 7. Chances of drawing a 7 next are 3 out of 51, because thee are now three 7s in the 51-card deck. If you do, chances of drawing another 7 are 2 out of 50, and the fourth one 1 out of 49. So far that's 6 out of 124950 or 1 out of 20825. But that's drawing four cards and getting four of a kind; a fifth card gives you more chances because you are allowed one card that's not a 7 in the first five you draw. How do you deal with that? OK, let's start over. First card is Y, which may be 7 or any other card. Success (4 of a kind) will be when you draw YYYYX, YYYXY, YYXYY, YXYYY, or YXXXX in order as you draw (X is the first denomination you draw that isn't Y). Each of these five cases has the same 1 out of 20825 chance as what I described above, which is the YYYYX case. Adding the five probabilities up, you get 1 out of 4165, or to put it another way, the odds of 4 of a kind are 4164 to 1 against you. Isn't Math fun?


What are the six through thirteen time tables?

6x0=0 7x0=0 8x0=0 9x0=0 10x0=0 11x0=0 12x0=0 13x0=0 6x1=6 7x1=7 8x1=8 9x1=9 10x1=10 11x1=11 12x1=12 13x1=13 6x2=12 7x2=14 8x2=16 9x2=18 10x2=20 11x2=22 12x2=24 13x2=26 6x3=18 7x3=21 8x3=24 9x3=27 10x3=30 11x3=33 12x3=36 13x3=39 6x4=24 7x4=28 8x4=32 9x4=36 10x4=40 11x4=44 12x4=48 13x4=52 6x5=30 7x5=35 8x8=40 9x5=45 10x5=50 11x5=55 12x5=60 13x5=65 6x6=36 7x6=42 8x6=48 9x6=54 10x6=60 11x6=66 12x6=72 13x6=78 6x7=42 7x7=49 8x7=56 9x7=63 10x7=70 11x7=77 12x7=84 13x7=91 6x8=48 7x8=56 8x8=64 9x8=72 10x8=80 11x8=88 12x8=96 13x8=104 6x9=54 7x9=63 8x9=72 9x9=81 10x9=90 11x9=99 12x9=108 13x9=117 6x10=60 7x10=70 8x10=80 9x10=90 10x10=100 11x10=110 12x10=120 13x10=130 6x11=66 7x11=77 8x11=88 9x11=99 10x11=110 11x11=121 12x11=132 13x11=143 6x12=72 7x12=84 8x12=96 9x12=108 10x12=120 11x12=132 12x12=144 13x12=156 6x13=78 7x13=91 8x13=104 9x13=117 10x13=130 11x13=143 12x13=156 13x13=169


25 percent of a class are girls - there are 13 girls - how many are in the class?

25% = 1/4, so 13 x 4 = 52 13 ÷ 25% = 13 ÷ 25/100 = 13 x 100/25 = 1300/25 = 52 people The above is a good answer (and correct in the solution) however, I feel the explanation of how the problem is solved isn't the most accurate way to solve this problem. As you stated 25% is 1/4, however, using this method to solve this problem will prove more complicated if the percentage becomes a more complicated number such as 33% or 35%, just a couple of examples. (always remember to change your percentage to decimal form before solving) The best way to solve such an equation is to remember the rules of Part, Base, Rate. Rate always being the percent (%) Remember to find the part the solution is b * r(%) = p Example, 25% of 100 would be 100 x .25 = 25 If you have a problem where the part and the rate are given, then you are looking for the base, or your starting number. As with the problem above, we know that 13 is the percentage of how many students are girls in a class, however we now need to solve to find out exactly how many students are in the class, since we are given the p (part) and the r (rate) we need to solve for base. b * .25 = 13. reverse the order (b = p / r) b = 13 / .25 b = 52 To check replace b with 52 and solve 52 * .25 = 13 Now let's take the same problem and search for rate if base and part are given. since we know the problem is b * r(%) = p, the we write it as follows 52 * r = 13 reverse the order once again, as with the first problem, remember this time we are searching for the rate. The equation would then be written (r = p / b) r = 13 / 52 0.25 = 13 / 52 Change the decimal .25 to a percentage by moving the decimal two places to the right... 25% to check just replace the original problem with your answer and solve... 52 * .25 = 13 Remember the 3 basic rules, b * r = p p / b = r p / r = b