No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
No, it is only divisible by 1, 2, 71, 142. In math terms, 'divisible' means divided without leaving a remainder.
No. 426 is only divisible by: 1, 2, 3, 6, 71, 142, 213, 426.
Yes, the result is 142.
1000 ÷ 7 = 142 remainder 6 So, there are 142 numbers between 1 and 1000 that are evenly divisible by 7. 1 x 7 = 7 2 x 7 = 14 3 x 7 = 21 ... 142 x 7 = 994
No. 142 is not evenly divisible by three.
No. 142 is not evenly divisible by nine.
No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
7 * 142 = 994
No, it is only divisible by 1, 2, 71, 142. In math terms, 'divisible' means divided without leaving a remainder.
No. 426 is only divisible by: 1, 2, 3, 6, 71, 142, 213, 426.
142, 284, 426 and keep adding 142 forever.
Yes.
142 of them.
I'm sorry ,but no.
The smallest 3-digit multiple of 7 is 105 = 15*7 The largest 3-digit multiple of 7 is 994 = 142*7 So there are 142-14 = 128 3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.
Yes as both divisible by 3 so 15/426 = 5/142