142 is not divisible by 3.
142 divided by 3 = 47 and 1/3
No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
No, it is only divisible by 1, 2, 71, 142. In math terms, 'divisible' means divided without leaving a remainder.
No. 426 is only divisible by: 1, 2, 3, 6, 71, 142, 213, 426.
Yes, the result is 142.
1000 ÷ 7 = 142 remainder 6 So, there are 142 numbers between 1 and 1000 that are evenly divisible by 7. 1 x 7 = 7 2 x 7 = 14 3 x 7 = 21 ... 142 x 7 = 994
No. 142 is not evenly divisible by three.
No. 142 is not evenly divisible by nine.
No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
7 * 142 = 994
No, it is only divisible by 1, 2, 71, 142. In math terms, 'divisible' means divided without leaving a remainder.
No. 426 is only divisible by: 1, 2, 3, 6, 71, 142, 213, 426.
142, 284, 426 and keep adding 142 forever.
Yes.
The number 284 is divisible by several integers, including 1, 2, 4, 71, 142, and 284. It is an even number, so it is divisible by 2. Additionally, since the sum of its digits (2 + 8 + 4 = 14) is not divisible by 3, it is not divisible by 3.
I'm sorry ,but no.
142 of them.
The smallest 3-digit multiple of 7 is 105 = 15*7 The largest 3-digit multiple of 7 is 994 = 142*7 So there are 142-14 = 128 3-digit multiples of 7, ie 128 3-digit numbers that are divisible by 7.