No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
Yes. 426/6 = 71
It is because 186426 = 3*62142 and 186426 = 9*20714.
it is but it comes out 106.5 which is uneven so probably not
81: 8 + 1 = 9 which is divisible by 9, so 81 is divisible by 9 162: 1 + 6 + 2 = 9 which is divisible by 9, so 162 is divisible by 9 199: 1 + 9 + 9 = 19 → 1 + 9 = 10 → 1 + 0 = 1 which is not divisible by 9, so 199 is not divisible by 9. 1125: 1 + 1 + 2 + 5 = 9 which is divisible by 9, so 1125 is divisible by 9. So 199 is the only one not divisible by 9.
No. But it is divisible by: 1 2 3 6 71 142 213 and 426.
Yes. 426/6 = 71
No, it is clearly a multiple of 2, making it not a prime number.
Yes.
1, 2, 3, 6, 9, 18, 71, 142, 213, 426, 639, 1278
Yes as both divisible by 3 so 15/426 = 5/142
It is because 186426 = 3*62142 and 186426 = 9*20714.
it is but it comes out 106.5 which is uneven so probably not
Well, honey, let's do some math here. The sum of the digits in 847 is 8+4+7=19, which is not divisible by 9. So, no, 847 is not divisible by 9. But hey, nice try for thinking about divisibility!
1,098 is divisible by 2 and 3. But im not sure about 6 and 9. But 5 and 10 are NOT divisible! I had this on my math homework!Study Link 1-5!
Oh, dude, numbers divisible by both 3 and 9 are multiples of the least common multiple of 3 and 9, which is 9. So, any number that is a multiple of 9 is also divisible by 3 and 9. Like, it's just basic math, nothing to lose sleep over.
yes - 91 times 9 is 819. It would be worth your while to learn how to divide by 9- ask your math teacher for a lesson.