ten 5/7 x 14 = 5/1 x 14/7 = 5 x 2/1 = 10
Let X be the Base! Given=> 14/2 = 5 => 14 = 5*2 => (14)x = (5)x * (2)x => 1.X^1+4.X^0 = 5.X^0 * 2.X^0 => X+4 = 5*2 => X+4 = 10 => X = 10-4 => X = 6 (Ans by Moody)
x-9 = 5 x = 5+9 x = 14
14, 19, 29, 44, 64, etc. 14 + (5 x 1) = 19 19 + (5 x 2) = 29 29 + (5 x 3) = 44 44 + (5 x 4) = 64
1 x 350 2 x 175 5 x 70 7 x 50 10 x 35 14 x 25 2 x 5 x 35 2 x 7 x 25 5 x 5 x 14 5 x 7 x 10 2 x 5 x 5 x 7
Assuming this is asking "What is the product of 5 x (7-3) x 14" the answer is: 5 x (7-3) x 14 5 X 4 x 14 20 x 14 (or 5 x 56) =280
14/5 x 5 = 70/5 = 14
yes 14 x 5 = 70
(x^2 + 9x +14) / (x+5) Factor (x^2 + 9x +14) [(x+7)(x+2)]/[(x+5)], x cannot equal -5
ten 5/7 x 14 = 5/1 x 14/7 = 5 x 2/1 = 10
3+x=5+9 5+9=14 3+X=14 14-3=11 X=11
less 5 is 14 basically means x-5=14. In which case, x=19 since you add 5 to both sides to get x by itself.
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Let X be the Base! Given=> 14/2 = 5 => 14 = 5*2 => (14)x = (5)x * (2)x => 1.X^1+4.X^0 = 5.X^0 * 2.X^0 => X+4 = 5*2 => X+4 = 10 => X = 10-4 => X = 6 (Ans by Moody)
2.8 x 5 = 14
x-9 = 5 x = 5+9 x = 14
7 x - 4 x + 2 x+5 = 2 x + 14 --- (1) Shift those terms containing "x" on left side and constants on other side 7 x - 4 x + 2 x - 2 x = 14 - 5 We will get 3 x = 9 Divide both sides by "3" we get; x = 3