(14x2)-9
It is a quadratic expression and when factored it is: (7x+5)(2x-7)
Since all of the coefficients are even, it is possible to factor out a 2.
Area of room = width * length = (2x-1)*(7x+3) = 14x2 + 6x - 7x - 3 = 14x2 - x - 3 sq feet
2/7 of 14 is 4 since 14(2/7)=14x2/7=2x2
14x2 - 5x + 1 = 2 : 14x2 - 5x - 1 = 0 Solving for the roots of a quadratic equation gives, x = [5 ± √(52 + 4x14)] ÷ 28 = (5 ± 9) ÷ 28 x = 14/28 = 1/2 and x = -4/28 = -1/7.
The value of x would be 0
(2x+5)(7x-3)=14x2 +29x-15
14x2 + 15x + 4 = (7x + 4)(2x +1)
-2
14x2
Can you clarify the question please? Is it (14 x 2)-1 + (1x-1) = 3x+1?
(2x - 7)(7x + 5)
(7x-3)(2x+5) 14x2 + 29x - 15, write 29x = 35x - 6x = 14x2 - 6x + 35x - 15 = (14x2 - 6x) + (35x - 15) = 2x(7x - 3) + 5(7x - 3) = (7x-3)(2x+5)
142 that's it duhhh
(7x - 8)(2x - 7)
(14x2)-9