(2x+5)(7x-3)=14x2 +29x-15
14x2 + 15x + 4 = (7x + 4)(2x +1)
f(x)=.39x
Apply the Distrubutive Property twice as you do when multiplying two-digit numbers Use the FOIL methed First Inner Outter Last. In the equation (3x + 4)(9x + 1) you get. (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 Now you multiply. 3x*9x = 27x^2 3x*1 + 9x*4 = 3x + 36x = 39x 1*4 = 4 So your entire answer is (3x)*(9x) + (3x)*1 + (9x)*4 + 4*1 = 27x^2 + 39x + 4
35 squared is 35 x 35 or 35^2 or 1,225.
14x2 - 39x - 35 = (7x + 5)(2x - 7)
It is a quadratic expression and when factored it is: (7x+5)(2x-7)
It is (7x+5)(2x-7) when factored
(7x + 5)(2x - 7)(2x-7)(7x+5)
39x-6
(2x+5)(7x-3)=14x2 +29x-15
28
3x2-39x-90 = (3x+6)(x-15) when factored
14x2 + 15x + 4 = (7x + 4)(2x +1)
41x
14x2
2x - 3= 9 x=