Q: What is 17100000 in words?

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17100 = 17100/1 = 17100/1 × 10/10 = 171000/10 = 17100/1 × 10²/10² = 1710000/100 = 17100/1 × 10³/10³ = 17100000/1000 ... = 17100/1 × 10ⁿ/10ⁿ There is no upper limit to this sequence: n = 0, 1, 2, 3, .... These numbers can be put in a one-to-one relationship with the counting numbers 1, 2, 3, ... The counting numbers can also be put in a one-to-one relationship with the whole numbers Therefore the sequence of fractions can be put in a one-to-one relationship with the whole numbers. Therefore the fraction of whole numbers which are in the sequence is 1. ----------- Let's try another approach: As 10 to some power is positive, there is no way we can change a negative number to make it positive by dividing by 10 to some power, therefore the solution numbers are all positive. As negative whole numbers make up half of the whole numbers, the fraction of whole numbers which are equivalent to 17100 when divided by a power of 10 is at most ½. The fraction of the ½ of the whole numbers which are positive can now be considered: After the nth whole number has been found which matches the criteria that is it equivalent to 17100 when it is divided by a power of 10, in total there are n numbers matching out of a total of 17100 × 10ⁿ⁻³ numbers (the value of the nth number); thus: The first number which meets the criteria is 171/10⁻² → the fraction is 1/171 The second number to meet the criteria is 1710/10⁻¹ → the fraction is 2/1710 The third number to meet the criteria is 17100/10⁰ → the fraction is 3/17100 The fourth number to match the criteria is 171000/10 → the fraction is 4/171000 The fifth number to match the criteria is 1710000/10²→ the fraction is 5/1710000 → For the nth match, the fraction is: n/(17100 × 10ⁿ⁻³) = (1/17100) × n/10ⁿ⁻³ This gives us a sequence of fractions: 1/17100 × 1/10⁻², 1/17100 × 2/10⁻¹, 1/17100 × 3/10⁰, 1/17100 × 4/10¹, 1/17100 × 5/10², ... = 100000/17100000, 20000/17100000, 3000/17100000, 400/17100000, 35/17100000, 6/17100000, .... Consider terms n and n+1: U{n} = (1/17100) × n/10ⁿ⁻³ = (1/17100) × 10 × n/10ⁿ⁻² U{n+1} = (1/17100) × (n+1)/10ⁿ⁻² U{n} - U{n+1} = (1/17100) × 10 × n/10ⁿ⁻² - (1/17100) × (n+1)/10ⁿ⁻² = (10n - (n+1))/(17100 × 10ⁿ⁻²) = (9n - 1)/(17100 × 10ⁿ⁻²) As n ≥ 1, 9n - 1 ≥ 9×1 - 1 = 8 → term n - term n+1 ≥ 8 > 0 → term n is larger than term n+1 for all n ≥ 1 Each of these terms is less than 1, and each term of the sequence is smaller than the previous one and so as n increases the value of the each term (the fraction of whole numbers which meet the criteria) tends towards 0. → The fraction of all whole numbers which equate to 17100 when divided by a power of 10 is as near enough to zero as make no odds. ie the fraction is so small it is effectively none of the whole numbers. ----------------------- This is a problem of dealing with the infinite.

what is 613.162 in words

3000 Characters is averaged between 2,000 words to 2,980 words.(allwordphone.com/count-words-characters.htm)

There are no decimal words. The fraction may be written in words as sixteen hundredths.

If the teacher asks for alternative words for a given word or words then he's asking for some synonyms or other words that mean the same as the ones you have.

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17100 = 17100/1 = 17100/1 × 10/10 = 171000/10 = 17100/1 × 10²/10² = 1710000/100 = 17100/1 × 10³/10³ = 17100000/1000 ... = 17100/1 × 10ⁿ/10ⁿ There is no upper limit to this sequence: n = 0, 1, 2, 3, .... These numbers can be put in a one-to-one relationship with the counting numbers 1, 2, 3, ... The counting numbers can also be put in a one-to-one relationship with the whole numbers Therefore the sequence of fractions can be put in a one-to-one relationship with the whole numbers. Therefore the fraction of whole numbers which are in the sequence is 1. ----------- Let's try another approach: As 10 to some power is positive, there is no way we can change a negative number to make it positive by dividing by 10 to some power, therefore the solution numbers are all positive. As negative whole numbers make up half of the whole numbers, the fraction of whole numbers which are equivalent to 17100 when divided by a power of 10 is at most ½. The fraction of the ½ of the whole numbers which are positive can now be considered: After the nth whole number has been found which matches the criteria that is it equivalent to 17100 when it is divided by a power of 10, in total there are n numbers matching out of a total of 17100 × 10ⁿ⁻³ numbers (the value of the nth number); thus: The first number which meets the criteria is 171/10⁻² → the fraction is 1/171 The second number to meet the criteria is 1710/10⁻¹ → the fraction is 2/1710 The third number to meet the criteria is 17100/10⁰ → the fraction is 3/17100 The fourth number to match the criteria is 171000/10 → the fraction is 4/171000 The fifth number to match the criteria is 1710000/10²→ the fraction is 5/1710000 → For the nth match, the fraction is: n/(17100 × 10ⁿ⁻³) = (1/17100) × n/10ⁿ⁻³ This gives us a sequence of fractions: 1/17100 × 1/10⁻², 1/17100 × 2/10⁻¹, 1/17100 × 3/10⁰, 1/17100 × 4/10¹, 1/17100 × 5/10², ... = 100000/17100000, 20000/17100000, 3000/17100000, 400/17100000, 35/17100000, 6/17100000, .... Consider terms n and n+1: U{n} = (1/17100) × n/10ⁿ⁻³ = (1/17100) × 10 × n/10ⁿ⁻² U{n+1} = (1/17100) × (n+1)/10ⁿ⁻² U{n} - U{n+1} = (1/17100) × 10 × n/10ⁿ⁻² - (1/17100) × (n+1)/10ⁿ⁻² = (10n - (n+1))/(17100 × 10ⁿ⁻²) = (9n - 1)/(17100 × 10ⁿ⁻²) As n ≥ 1, 9n - 1 ≥ 9×1 - 1 = 8 → term n - term n+1 ≥ 8 > 0 → term n is larger than term n+1 for all n ≥ 1 Each of these terms is less than 1, and each term of the sequence is smaller than the previous one and so as n increases the value of the each term (the fraction of whole numbers which meet the criteria) tends towards 0. → The fraction of all whole numbers which equate to 17100 when divided by a power of 10 is as near enough to zero as make no odds. ie the fraction is so small it is effectively none of the whole numbers. ----------------------- This is a problem of dealing with the infinite.

What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.What words? Roman words are simply words written in the Latin language. You have to be specific as to what words you want.

Linking words that are similar in meaning.

last words final words dying words

new words current words archaic words absolete words

yes! no!

Words that children use to see the response from the hearer. The words are usually less-sanitized words, such as gutter-words, bathroom words, sexuality words.

Such words are called "conjunctions" - examples are .... and, but, if

"Vocabulary words" refers to any words a person knows, while "study words" are specific words someone is actively learning. Study words can be part of a person's vocabulary, but not all vocabulary words are study words.

Compound words are linked words.

people's words.

Words = mots