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Why does a cube root only have one value?
Because the cube of a positive number is positive and the cube of a negative number is negative.-------------------------------------------------------------------------------------------------------------------------------Every number has THREE cube roots. However, (at least) two of the three are complex numbers.For example, the cube roots of 8 are 2, (-1 + √3 i) and (-1 - √3 i) with i² = -1:2³ = 2 × 2 × 2 = 8(-1 + √3 i)³ = (-1 + √3 i)(-1 + √3 i)(-1 + √3 i)= (-1 + √3 i)((-1)² - 2√3 i + 3i²)= (-1 + √3 i)(1 - 2√3 i -3)= (-1 + √3 i)(-2 - 2√3 i)= (-1 + √3 i)(-1 - √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8(-1 - √3 i)³ = (-1 - √3 i)(-1 - √3 i)(-1 - √3 i)= (-1 - √3 i)((-1)² + 2√3 i + 3i²)= (-1 - √3 i)(1 + 2√3 i -3)= (-1 - √3 i)(-2 + 2√3 i)= (-1 - √3 i)(-1 + √3 i)2= ((-1)² - 3i²)2= (1 + 3)2= 4 × 2 = 8
How many different equations can be made with the numbers 0123?
A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!
What is 1 half add 1 and a half times by 2?
1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2
Adding two cube's equal to 9 i want two answers?
1^3 + 2^3 = 1 + 8 = 9 2^3 + 1^3 = 8 + 1 = 9 There is also: 1^3 + (-1 + i√3)^3 = 9 1^3 + (-1 - i√3)^3 = 9 (-1/2 + i√3/2)^3 + 2^3 = 9 (-1/2 - i√3/2)^3 + 2^3 = 9
How do you get the answer 7 using only numbers -4-3-2-1?
[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7
How many different combinations can you make with 2 4s 1 3 and 1 2?
1 1 1 2 1 3 1 4 2 1 2 2 2 3 2 4 3 1 3 2 3 3 3 4 4 1 4 2 4 3 4 4
What are the next three numbers in the given series 1 1 2 1 2 2 3 1 2 2 3 2 3 3 4 1 2 2 3 2 3 3?
434
How many different equations can be made with the numbers 0123?
A huge number. 0 + 1 + 2 = 3 0 + 2 + 1 = 3 1 + 0 + 2 = 3 1 + 2 + 0 = 3 2 + 0 + 1 = 3 2 + 1 + 0 = 3 -0 + 1 + 2 = 3 -0 + 2 + 1 = 3 1 - 0 + 2 = 31 + 2 - 0 = 32 - 0 + 1 = 32 + 1 - 0 = 3 0 - 1 + 3 = 2 0 + 3 - 1 = 2 -1 + 0 + 3 = 2 -1 + 3 + 0 = 2 3 + 0 - 1 = 2 3 - 1 + 0 = 2 -0 - 1 + 3 = 2-0 + 3 - 1 = 2-1 - 0 + 3 = 2-1 + 3 - 0 = 23 - 0 - 1 = 23 - 1 - 0 = 2 0 - 2 + 3 = 1 0 + 3 - 2 = 1 -2 + 0 + 3 = 1 -2 + 3 + 0 = 1 3 + 0 - 2 = 1 3 - 2 + 0 = 1 -0 - 2 + 3 = 1-0 + 3 - 2 = 1-2 - 0 + 3 = 1-2 + 3 - 0 = 13 - 0 - 2 = 13 - 2 - 0 = 1 1 + 2 - 3 = 0 1 - 3 + 2 = 0 2 + 1 - 3 = 0 2 - 3 + 1 = 0 -3 + 1 + 2 = 0 -3 + 2 + 1 = 0 For each of these equations there is a counterpart in which all signs have been switched. For example 0 + 1 + 2 = 3 gives -0 - 1 - 2 = -3and so on. Now, all of the above equations has three numbers on the left and one on the right. Each can be converted to others with two numbers on each side. For example:the equation 0 + 1 + 2 = 3 gives rise to0 + 1 = 3 - 20 + 1 = -2 + 30 + 2 = 3 - 10 + 2 = -1 + 31 + 2 = 3 - 01 + 2 = -0 + 3-0 + 1 = 3 - 2-0 + 1 = -2 + 3-0 + 2 = 3 - 1-0 + 2 = -1 + 31 + 2 = 3 + 01 + 2 = +0 + 3 As you can see, the number of equations is huge!
What is 1 half add 1 and a half times by 2?
1/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/21/2 + (11/2)*2 = 1/2 + (3/2)*2 = 1/2 + 3 = 31/2
Adding two cube's equal to 9 i want two answers?
1^3 + 2^3 = 1 + 8 = 9 2^3 + 1^3 = 8 + 1 = 9 There is also: 1^3 + (-1 + i√3)^3 = 9 1^3 + (-1 - i√3)^3 = 9 (-1/2 + i√3/2)^3 + 2^3 = 9 (-1/2 - i√3/2)^3 + 2^3 = 9
What is 2 to the 1 to the 3?
2^1^3=2 (2^1)^3=6
How do you get the answer 7 using only numbers -4-3-2-1?
[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7[(-4) + (-3)]*[(-2 - (-1)] = (-4 -3)*(-2 + 1) = -7*-1 = +7
what - 1 =2?
The answer is 3, because 3 - 1 = 2.
What are the possible ways that 12 chairs and an odd number of tables can be arranged?
Assuming that there is at least one chair at each table, the answer is that there are 37 ways. 12 1 1 10, 1 2 9, 1 3 8, 1 4 7, 1 5 6, 2 2 8, 2 3 7, 2 4 6, 2 5 5, 3 3 6, 3 4 5, 4 4 4, 1 1 1 1 8, 1 1 1 2 7, 1 1 1 3 6, 1 1 1 4 5, 1 1 2 2 6, 1 1 2 3 5, 1 1 2 4 4, 1 1 3 3 4, 1 2 2 2 5, 1 2 2 3 4, 1 2 3 3 3, 2 2 2 2 4, 2 2 2 3 3, 1 1 1 1 1 1 6, 1 1 1 1 1 2 5, 1 1 1 1 1 3 4, 1 1 1 1 2 2 4, 1 1 1 1 2 3 3, 1 1 1 2 2 2 3, 1 1 2 2 2 2 2, 1 1 1 1 1 1 1 1 4, 1 1 1 1 1 1 1 2 3, 1 1 1 1 1 1 2 2 2, 1 1 1 1 1 1 1 1 1 1 1 2.
What is the levelling system in call of duty modern warfare 3?
private ""1 " "2 private 1st class "" 1 "" 2 specialist "" 1 "" 2 corporal ""1 ""2 sergeant "" 1 "" 2 staff sergeant "" 1 "" 2 "" 3 sergeant 1st class "" 1 "" 2 "" 3 master sergeant "" 1 "" 2 "" 3 1st sergeant "" 1 "" 2 "" 3 sergeant major "" 1 "" 2 "" 3 command sergeant major "" 1 "" 2 "" 3 2nd lieutenant "" 1 "" 2 "" 3 1st lieutenant "" 1 "" 2 "" 3 captain "" 1 "" 2 "" 3 major "" 1 "" 2 "" 3 lt. colonel "" 1 "" 2 "" 3 colonel "" 1 "" 2 "" 3 brigader general "" 1 "" 2 "" 3 major general "" 1 "" 2 "" 3 lt. general "" 1 "" 2 "" 3 general "" 1 "" 2 "" 3 commander PRESTIGE MODE( starts from begging) hope you appretiate that, took me ages :-)
What is the answer to three divided into one and a half?
Divided by 3 ÷ 1 1/2 = 2 Divided into 1 1/2 = 3/2 3/2 ÷ 3 = 1/2
What are the factors of 3 and negative 2?
For 3: 1 and 3. For -2: 1, 2, -1, -2
