16.67%
Think about it; there is a 1 of 6 chance it lands on a particular number, like 4. there are 3 even numbers; 2,4,6. 1/6 chance for 2, 1/6 chance for 4, 1/6 chance for 6. 1/6+1/6+1/6=3/6 or 1/2. solve from there.
The chance of rolling it each time is (1/6). So the chance of rolling it 4 times in a row is(1/6) x (1/6) x (1/6) x (1/6) = (1/1296) = 0.0007716 = 0.0772 % (rounded)The chance of rolling it each time is the same. It's not affected by what came before,since dice have no memory.
1/6 as a percentage = 100*1/6 = 100/6 = 16.666... which, to two decimal places, is 16.67
1 : 2 : 3 That shows us there are 3 possibilities of total 6 (1+2+3) and: a) first one has 1 / 6 chance, b) second one has 2 / 6 chance, c) third has 3 / 6 chance.
1/6+1/6=1/3
Think about it; there is a 1 of 6 chance it lands on a particular number, like 4. there are 3 even numbers; 2,4,6. 1/6 chance for 2, 1/6 chance for 4, 1/6 chance for 6. 1/6+1/6+1/6=3/6 or 1/2. solve from there.
Chance Caldwell is 6' 1".
1/6 chance. Or a 16% chance
2 in 6 or 1 in 3 There is 1 in 6 chance to get a 4 and a 1 in 6 chance to get a 6, combined it is 2 in 6
1 in 6 = 16.67%
1/6 = 16.67%
The chance of rolling it each time is (1/6). So the chance of rolling it 4 times in a row is(1/6) x (1/6) x (1/6) x (1/6) = (1/1296) = 0.0007716 = 0.0772 % (rounded)The chance of rolling it each time is the same. It's not affected by what came before,since dice have no memory.
Expressed as a percentage, 1/6 x 100 = 16.6 recurring (that is, 16.6666...) percent.
1/6 or 50%
A 1 in 6 chance.
100/6=16.6666667%
The chance of getting a 2 on the first cube is 1 out of 6.The chance of getting a 2 on the second cube is 1 out of 6.The chance of getting a 2 on both cubes is (1/6) x (1/6) = 1/36 = 2.78% (rounded)