That would be expressed as "1000!", or "one thousand factorial". The number itself would be far too large to enter here.
Π5j=1 (j)=1x2x3x4x5=5!=120
120, 1X2X3X4X5=120. 16 fators
(5*11)-5+5-5+5 I am sure that the number 11 is not allowed in this question. How about this: 5! - 55 - (5+5) = 55 For clarity, 5 factorial or 5! = 1x2x3x4x5 = 120
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That would be expressed as "1000!", or "one thousand factorial". The number itself would be far too large to enter here.
The formula for multiplying consecutive numbers from 1 to n is n factorial, denoted as n!. In this case, the formula for 1x2x3x4x5 is 5! = 120.
Π5j=1 (j)=1x2x3x4x5=5!=120
120, 1X2X3X4X5=120. 16 fators
Since all letters are distinct, there are 120.1x2x3x4x5=120, not 5. CHINA=5 letters. So do the same formula (1x2x3x4x5) but the answer is 120.
The number 21 has only four factors: 1, 3, 7, and 21. Many number have more than four factors. Among them are 1x2x3x4x5 = 120.
(5*11)-5+5-5+5 I am sure that the number 11 is not allowed in this question. How about this: 5! - 55 - (5+5) = 55 For clarity, 5 factorial or 5! = 1x2x3x4x5 = 120
positive 5the absolute value of -5 is 5.
With a scientific calculator. The actual calculation is somewhat complicated, so you wouldn't normally want to do it yourself. However, if you really want to know it, the formula is the following infinite series: sin(x) = x - x3/3! + x5/5! - x7/7! + x9/9! ... The angle x has to be in radians (to convert degrees to radians, multiply by pi/180), and the exclamation is the factorial function, for example, 5! = 1x2x3x4x5. You add as many terms as required to get the desired accuracy.
Assuming the last ball is from a group of 40, and the first 5 are selected without replacement: for 1 ticket P = 1/ (40x(40x39x38x37x36)/(1x2x3x4x5)) = (39x38x37x36) = 1/78,960,960 Assuming none of the 10 are repeats your ans is 10 x 1/78,960,960 = 1/7,896,096 rounding you have 1 chance in 8 million to win.
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