271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
To find the fraction of 4-digit natural numbers with a product of their digits that is even, we first need to determine the total number of 4-digit natural numbers. There are 9000 such numbers (from 1000 to 9999). Next, we consider the conditions for the product of digits to be even. For a number to have an even product of digits, at least one of the digits must be even. There are 5 even digits (0, 2, 4, 6, 8) and 5 odd digits (1, 3, 5, 7, 9). Therefore, the fraction of 4-digit natural numbers with an even product of digits is 5/10 * 9/10 * 9/10 * 9/10 = 3645/9000 = 809/2000.
Yes. Natural numbers, or counting numbers, cannot produce non-natural numbers, or complex numbers, through methods of multiplication or addition. However 5 divided by 3 creates the complex number 1.666666.... So division of two naturals can produce a complex. Also 6 minus 10 creates -4 which is not a natural number.
The numbers are: 28/5 and 3/5
5+5 = 10 (Sum is ten)5*5 = 25 (Product is 25)*this product is maximum for all any 2 real numbers that == 10
Good question. 1+2+3+4+5=155=15 So the product of first five natural numbers is fifteen Natural numbers starts from one So we add first five natural numbers and get the right answer is fifteen
The last digit in the product of the first 20 odd natural numbers can be determined by looking at the pattern of the units digit in the multiplication of consecutive odd numbers. The units digit of the product of consecutive odd numbers alternates between 1 and 5. Since there are 10 odd numbers between 1 and 19, and 20 is also an odd number, the last digit in the product of the first 20 odd natural numbers is 5.
Zero. Any five consecutive natural numbers will contain at least one multiple of 2 and at least one multiple of 5, meaning that the product will be a multiple of 10.
271 of the first 1000 natural numbers contain at least one digit 5. That is 27.1 % of them.
The first four prime numbers are 2, 3, 5, 7. The product of these numbers is 2 x 3 x 5 x 7 = 210
The product of the first three prime numbers (2, 3, and 5) is 30.
The product of a natural number and all of the lesser natural numbers is called the factorial of the number. It is often represented with an exclamation point. So:5! = 5 * 4 * 3 * 2 * 1
Sure thing, honey. The first four prime numbers are 2, 3, 5, and 7. Multiply those bad boys together and you get 210. And wouldn't you know it, 210 is a composite number because it can be divided by numbers other than 1 and itself. Math can be a real hoot sometimes, can't it?
The first five prime numbers are 2, 3, 5, 7, 11. The product of these five numbers is equal to 2 x 3 x 5 x 7 x 11 = 2310.
The series of first 5 whole numbers is: 0 1 2 3 4.The product of first 5 whole numbers will be 0.It is because 0 is also a whole number and any thing multiplied by 0 will give out answer to be 0,no matter how long the series is.
The product of numbers is the multiplication of the numbers. 1*2*3*4*5*6= 720.
the product of 3 whole numbers is 5. Their sum is 7. what are the numbers