24000
Two of them and they are 23
When rounding 233.356 to two significant figures, we start counting from the leftmost non-zero digit. In this case, the first two digits are 2 and 3. The digit following the last significant figure (3) is 3, which is less than 5, so we do not round up. Therefore, 233.356 rounded to two significant figures is 230.
4 of them.
108.6957
23
23.43 rounded to two significant figures is 23.
Two.
Two of them and they are 23
To determine the number of significant figures in the product of 0.1400, 6.02, and (10^{23}), we need to identify the significant figures in each number. The number 0.1400 has four significant figures, 6.02 has three significant figures, and (10^{23}) has one significant figure (as it is a power of ten). The product will have the same number of significant figures as the term with the least significant figures, which is 6.02 with three significant figures. Therefore, the final product will have three significant figures.
0.0342
0.0023
0.0175
3 of them.
Using eight significant figures, there are 6.0221421 X 10^23 carbon atoms present in a mole of 12c.
When rounding 233.356 to two significant figures, we start counting from the leftmost non-zero digit. In this case, the first two digits are 2 and 3. The digit following the last significant figure (3) is 3, which is less than 5, so we do not round up. Therefore, 233.356 rounded to two significant figures is 230.
0
Avogadro's number is typically written as 6.022 x 10^23, meaning it has four significant figures, 6, 0, 2, and 2.