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34 is halfway between 23 and 45 inclusively.Therefore, 34 x 2 = 68
Let x = one of the integers x + 1 = the other integer x + x + 1 = 45 2x = 44 x = 22 x + 1 = 23
1 x 45 = 45 2 x 45 = 90 3 x 45 = 135 4 x 45 = 180 5 x 45 = 225 6 x 45 = 270 7 x 45 = 315 8 x 45 = 360 9 x 45 = 405 10 x 45 = 450 11 x 45 = 495 12 x 45 = 540
The first ten positive integer multiples of 45 are as follows: 1 x 45 = 45 2 x 45 = 90 3 x 45 = 135 4 x 45 = 180 5 x 45 = 225 6 x 45 = 270 7 x 45 = 315 8 x 45 = 360 9 x 45 = 405 10 x 45 = 450
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