Let the required number be x. According to question: When x is added to -26 we get 14. Therefore, x + (-26) = 14 x - 26 = 14 x = 14 + 26 = 40. So, 40 must be added to -26 to get 14.
-2x - 14 = 26 -2x = 26 + 14 x = -40/2 x = -20
Ans: 14 boys & 12 girls. Here's how: Assume x boys. So 26 - x girls. x boys & i rect per boy --- 4x sides; 26 - x girls & i tri per girl --- 3(26 -x) sides Hence, 4x + 3(26 - x) = x + 78 sides in all, and this = 92. So x = 14
It is 52
702 = 26 x 27; 210 = 14 x 15.
Let the required number be x. According to question: When x is added to -26 we get 14. Therefore, x + (-26) = 14 x - 26 = 14 x = 14 + 26 = 40. So, 40 must be added to -26 to get 14.
-2x - 14 = 26 -2x = 26 + 14 x = -40/2 x = -20
364 is one answer 14 x 26 = 364 26 x 14 = 364 Half that also works ... 182/14 = 13 182/26 = 7
- 2x - 14 = 26 Switch all signs: 2x + 14 = - 26 Subtract 14 from both sides: 2x = -26 - 14 = - 40 Divide both sides by 2: x = - 40/2 = - 20
364 = 28 x 13 = 26 x 14
If x = 3, (4 x 3) + 14 = 26 and (6 x 3) + 8 = 26.
-26
As there is a common factor of 2, the LCM is 14 x 26/2 ie 182
2
1, 2, 4, 7, 13, 14, 26, 28, 52, 91, 182, 364.
1 stone is equal to 14 pounds. Therefore, 26 stone is equal to 364 pounds (26 x 14 = 364).
Order the numbers by size. Then the median of three numbers must be the middle number. So the second number is 7. The mean is 11 so their sum is 3*11 = 33 so the sum of the first and third is 33-7 = 26. The range is 14 so if one of the numbers is x, another must be x+14. Now x must be the smallest or the second (=7) [It can't be the largest because x+14 is bigger] If x = 7 then x+14 = 21 and the first must be 26-21 = 5 but then the range becomes 16. So x is not 7. So x is the smallest number, and x+x+14 = 26 ie 2x+14=26 or 2x = 12 or x = 6 Then the third number is x+14 = 20 So the three are 6,7 and 20.