Let the required number be x.
According to question:
When x is added to -26 we get 14.
Therefore,
x + (-26) = 14
x - 26 = 14
x = 14 + 26 = 40.
So, 40 must be added to -26 to get 14.
-40
26 because all of the other numbers are added from 2. for example, 14+2=16, and 16+2=18
4
26
-2x - 14 = 26 -2x = 26 + 14 x = -40/2 x = -20
-40
26
It is: 14+20 = 34
26 because all of the other numbers are added from 2. for example, 14+2=16, and 16+2=18
2
2
4
26 hundreds (2600)
40
26
It is: (14+38)/2 = 26
Order the numbers by size. Then the median of three numbers must be the middle number. So the second number is 7. The mean is 11 so their sum is 3*11 = 33 so the sum of the first and third is 33-7 = 26. The range is 14 so if one of the numbers is x, another must be x+14. Now x must be the smallest or the second (=7) [It can't be the largest because x+14 is bigger] If x = 7 then x+14 = 21 and the first must be 26-21 = 5 but then the range becomes 16. So x is not 7. So x is the smallest number, and x+x+14 = 26 ie 2x+14=26 or 2x = 12 or x = 6 Then the third number is x+14 = 20 So the three are 6,7 and 20.