0 oC = 273 K
The degree units are the same foir both systems. Hence
298K - 273K = 25 oC ( This is approximately room temperature).
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A = k (b/c)'k' is some constant number.
Angle and its complement have a sum of 90 degrees: A+C = 90 Angle plus five times its complement is 298 degrees: A+5C = 298 Subtract first equation from the second: 4C = 208 C = 52 So, the complement is 52 degrees and the angle is 38 degrees
B, C, D, E, H, I, K, O, X, (B, C and K not in all fonts) c, l, o, x
use this strategy: integral of (b^x) dx = (b^x)/ln(b) + K [K is integration constant, b is not a variable]rewrite (1/c)^(1-x) = ((1/c)^1)*((1/c)^(-x)) = (1/c)*(c^x). (1/c) is a constant, so bring outside the integral, then let b = c in the formula above, and you have (1/c)*(c^x)/ln(c) + K
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