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0 oC = 273 K

The degree units are the same foir both systems. Hence

298K - 273K = 25 oC ( This is approximately room temperature).

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lenpollock

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7mo ago
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8y ago

It is 24.85 Degrees Celsius.

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Q: What is 298 k in C?
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What state is oxygen at 298 K?

Oxygen is a gas at 298 K.


Convert this temperature to the Kelvin scale. 25c?

add 273 to get from C to K 25 + 273 = 298 Kelvins


What is 298 Fahrenheit converted into kelvins?

298 degrees Fahrenheit = 420.93 K.


Is the element chlorine a solid liquid or gas at room temp 298 K?

Chlorine is a gas at room temperature and pressure. Its melting point is −101.5 °C while its boiling point is −34.04 °C. So at 25 °C, it would be in the gaseous state.


Which equation represents an exothermic reaction at 298 K?

An exothermic reaction is one where heat is released to the surroundings. An example of an exothermic reaction equation at 298 K is: 2H2(g) + O2(g) -> 2H2O(l) + heat


How do you convert 298 degrees Fahrenheit to kelvin?

To convert Fahrenheit to Kelvin, you can use the formula K = (F - 32) x 5/9 + 273.15. Plugging in 298 degrees Fahrenheit gives you K = (298 - 32) x 5/9 + 273.15, which equals approximately 425.37 Kelvin.


What is room temperature in kelvin?

If we assume "room temperature" to be 25 °C (77 °F) then that would equate to 298.15 K. Different areas assume different standard "room temperature" - but it usually falls between 20 °C (293.15 K) and 30 °C (303.15 K)


What would you change 298 kelvin into degrees celsius?

Use this equation to convert Kelvin to degrees Celsius/Centigrade: [°C] = [K] - 273.15


A balloon that contains 0.75 L of a gas at 25°C is cooled to –100°C. Calculate the new volume of the balloon.?

Using the ideal gas law, we can calculate the new volume of the balloon. Given that the initial volume is 0.75 L, the initial temperature is 25°C (298 K), and the final temperature is -100°C (173 K), we can use the equation (V1/T1) = (V2/T2) to find the new volume. Plugging in the values, we get V2 = (0.75 L * 173 K) / 298 K ≈ 0.44 L.


If the Temperature 25.3 C the temperature equals approximately?

It is approximately 25°C. In Fahrenheit it is approximately 78°F It is also approximately 298 K


What is the numerical value of Kw at 298 k?

The value of Kw (ion product of water) at 298 K is approximately 1.00 x 10^-14.


A 150.0 ML sample of gas is collected at 1.20 ATM and 25 C what volume does the gas have at 1.50 ATM and 20.0 Ccould you show work?

To solve this problem, we can use the combined gas law formula: (P1 × V1) / (T1) = (P2 × V2) / (T2) Plugging in the values, we get: (1.20 ATM × 150.0 mL) / (298 K) = (1.50 ATM × V2) / (293 K) Solving for V2, we get V2 ≈ 120.0 mL. Therefore, the gas sample would have a volume of approximately 120.0 mL at 1.50 ATM and 20.0°C.