Provided that the range of g(x) is the domain of f(x) then it is the composite function, called f of g of x.Note that f(g(x) ) is not the same as g(f(x).For example, if f(x) = x + 2 and g(x( = 3*x for real x, thenf(g(x)) = f(3*x) = 3*x + 2while g(f(x)) = g(x + 2) = 3*(x + 2) = 3*x + 6
x^2+10
The GCF is 14fg2
1 g = 1,000 mg 2 g = 2,000 mg 3 g = 3,000 mg . . . 100 g = 100,000 mg
Percent means out of 100 → 3 percent of 100 g = 3/100 × 100 g = 3 g
If G + 5 = g - 2 then G = g + 3 and g = G - 3
36g2h2 = 2*2*3*3*g*g*h*h provided g and h are prime.
Let f ( x ) = 3 x 5 and g ( x ) = 3 x 2 4 x
200 g in the ratio 8 : 3 : 2 is approx 123 g, 46 g and 31 g.
V1 ______________________________ E,G,G,G G,A,A,A E,G,G,G G,A,A,A A A,A,A,G,G,F,F,G,G E G,G,G,G,A,A,B,B,G,C,C C,A,C,C,D D D,D,D,E,E,E,D,D,C E,G,A,A A,G,E,E E,G,A,A A,G,E,F,E,D,C,C V2 (it might be the same as the first verse though, not entirely sure.) ___________________ E,G,G,G,G,A,A,A E,G,G,C,B,B,A,A G,A,A,A,A,A,G,G,E,A,G,F,E,D E,G,G,G,G,A,A,B G,C,C,C,A,G,C,C,D C,D,D,D,D,E,E,E,D,D,C E,G,A,A A,G,E,E E,G,A,A A,G,E,F,E,D,C,C that's all i knw :)
|---------------------------------------------0--2--3------E |------------------------------------0--1--3---------------A |------------------------------0--2------------------------D |------------------------0--2------------------------------G |---------------0--2--3------------------------------------B |------0--2--3---------------------------------------------e re...
No not yet... but right now they have the 1 g, 2 g, 3 g, and 4 g
Use any 3 ascending notes such as B A G A B B B. A A A. B B B. B A G A B B B. B B B B A G.Another answer:G F E F G G G F F F G G G G F E F G G G F F G F E (flat)dcbc ddd ccc Dee dcbc ddd ccdc b that's how you play Mary had a little lamb!!
G#########################################################D#2###2#2###3#5###########################################A#################3###3#3###2###############2#3###5(\)####E#############################5###3###3#3#################(4x) (last with slide down at end.Chords: G Am C D (x2)
I do not think so. sorry :)
The inverse of a function (G(x)) can be found by switching the roles of (x) and (y) and solving for (y). Given the function (G(x) = -\frac{4}{3}x + 2), let's find its inverse: Step 1: Replace (G(x)) with (y): [y = -\frac{4}{3}x + 2] Step 2: Swap (x) and (y): [x = -\frac{4}{3}y + 2] Step 3: Solve for (y): [x - 2 = -\frac{4}{3}y] [-\frac{3}{4}(x - 2) = y] So, the inverse function (G^{-1}(x)) is: [G^{-1}(x) = -\frac{3}{4}(x - 2)]
explain what each of the following symbols (show in [ ] ) represents: CH4(g) [+] [2]O2(g) -> CO2(g) +2H[2]O(g)