If G + 5 = g - 2 then G = g + 3 and g = G - 3
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what is the domain of g(x) equals square root of x plus 1? √(x+1) ≥ 0 x+1≥0 x≥-1 Domain: [-1,∞)
For these type of calculations its just a straightforward substitutation. So for g=5 we put in 5 for g. So that's 11(5) = 55 if you evaulated the expression for g=7 it would be 11(7) = 77 etc... for all whole number values of g.
If you are saying that the original function is g(x) = 0.75x + 2, then the inverse, or g'(x), would be equal to (4/3)(x - 2).