The solution to the problem -10-2x-45 is 80 from the simplified form (90-10).
2x * 2x (2*2=4) therefore, 2x*2x equals 4x2.
Assuming the 78 is 80% of the class and a 60 is passing: 78*.80 + x*.20 = 60 .2x + 62.4 = 60 .2x = -2.4 x = -12 So you cannot really fail the class. (If you need a 70 to pass the class you need at least a 38.)
2x-4y=-8-2x......-2x-4y=-2x-8(-4y)/-4 | (-2x-8)/-4y=1/2x+2
-2x-2x-2x-2x-2=-32
6x + 12x + 2x = 80 20x = 80 x = 4
-80
Let the length be x:- 2(x+40) = 240 2x+80 = 240 2x = 240-80 2x = 160 x = 80 cm Check: 80+80+40+40 = 240 cm
7x - 2x = 80 subtracting like terms, 5x = 80 divide both sides by 5 x = 16
The solution to the problem -10-2x-45 is 80 from the simplified form (90-10).
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Let the lengths be 2x and 5x If: 2*(2x+5x) = 224 then x = 16 So therefore the lengths are 32 and 80 because 32+80+32+80 = 224
80 = 2x + 2(x+6)80 = 4x + 1268 = 4xx = 17Dimensions are x by (x+6), so:17x23Check:Permimeter = 2x + 2y (17*2)+(23*2) = 80, therefore correct
since X = 40% , 2X = 80% therefore 10% of 2X = 8% 8% of 125 = 10
Subtract 2x from each side: 30 = 10x - 50;Add 50 to each side: 80 = 10xDivide each side by 10: 8 = x
2x²-12x-80 First factor out 2 from each term to make it easier to handle. 2(x²-6x-40) What two number that are 6 apart (since the 6 is negative) multiply to make 40? 10 and 4 work. Since the 6 is negative, put the negative with the higher number, and you're done. 2(x-10)(x+4) ◄ Check it 2 (x² - 10x + 4x - 40) 2 (x² - 6x - 40) 2x² - 12x - 80 ■
Let the length be x+2 and the width be x: (x+2)*x = 80 x2+2x = 80 x2+2x-80 = 0 Solving the above with the quadratic equation formula works out as: x = -10 or x = 8, so it must be the latter because dimensions can't be negative. Therefore: length = 10 inches