Subtract 2x from each side: 30 = 10x - 50;
Add 50 to each side: 80 = 10x
Divide each side by 10: 8 = x
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z=pq
2z+6z+24=0 8z+24=0 8z= -24 z= - 3
why will the equations x+14=37 and x-14=37 have different solutions for x
Set up the equation and solve for z: 28 + z = 56 (next, subtract 28 from each side of the equaition to solve) z = 28
3x-2 = 2x+3 3x-2x = 3+2 x = 5