Let square = [x] -4+3*(-2)*[-4]+[3x-2x]=-4-6-2+[x]=-12+[x]The answer is negative 12 plus squared x.
(2x+3)(2x+4)
(x2-7x+12)/(x2-2x-3)factor the numerator & denominator:(x-4)(x-3)/(x-3)(x-1)now reduce:(x-4)(x-3)/(x+1)(x-3)(x-4)/(x+1)
You have to experiment with different factors of 2, and different factors of 15. In this case, 2x2 - 11x + 15 = (2x - 5) (x - 3)
By factoring I get x-3 divided by x+3
(2x-3)(x-1)
(2x - 1)(x + 3)
2x squared minus 5x minus 3 factored is (2x+1)(x-3).
(2x - 3)(x + 2)
(2x - 3)(x + 2)
2x squared - 5x - 3 = (2x +1)(x -3)
(x - 2)(2x - 3)
(x - 3)(2x - 7)
(4x - 3)(2x + 3)
(x + 3)(3x - 2)
2(x - 3)(x - 3)
Numerator = (x + 4)*(x + 3) Denominator = (2x - 1)*(x + 3) Calcelling out the common factor, (x + 3), the answer is (x + 4) divided by (2x - 1) provided x ≠0.5