f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.
length=2x width=x perimiter=2x+2x+x+x=30= 6x=30 divide by 6, x=5 area=length times width= 2(5)times 5 = 10 times 5= 50yd
Let x represent the number. 2 times the number would be 2x, and 5 times the number would be 5x. The sum of the two would be 2X + 5x = 7x
2x+5y=20 Solve for y -2x -2x 5y=20-2x 5 5 5 y=4-2x 5
Simplifying 4x + -5 = 2x + 7 Reorder the terms: -5 + 4x = 2x + 7 Solving -5 + 4x = 7 + 2x Move all terms containing x to the left, all other terms to the right. Add '-2x' to each side of the equation. -5 + 4x + -2x = 7 + 2x + -2x Combine like terms: 4x + -2x = 2x -5 + 2x = 7 + 2x + -2x Combine like terms: 2x + -2x = 0 -5 + 2x = 7 + 0 -5 + 2x = 7 Add '5' to each side of the equation. -5 + 5 + 2x = 7 + 5 Combine like terms: -5 + 5 = 0 0 + 2x = 7 + 5 2x = 7 + 5 Combine like terms: 7 + 5 = 12 2x = 12 Divide each side by '2'. x = 6 (your answer)
are you trying to say (-2x) times 1 times (x-5)? if so, the answer is -2xsquared + 10x
-3(x-5)=2x -3x+15=2x 15=5x x=3
3 = 2x + 5 -5 -5 -2 = 2x ---------- 2 x = -1
f(x)= (x-7) /(-2x+7)(2x+5) set -2x+7=0 -2x=-7 x=7/2 set 2x+5=0 2x=-5 x=-5/2 x=7/2 and x=-5/2 are vertical asymptotes.
18x + 5
length=2x width=x perimiter=2x+2x+x+x=30= 6x=30 divide by 6, x=5 area=length times width= 2(5)times 5 = 10 times 5= 50yd
Let x represent the number. 2 times the number would be 2x, and 5 times the number would be 5x. The sum of the two would be 2X + 5x = 7x
4(x + 5) = 2x + 8 4x + 20 = 2x + 8 2x = -12 x = -6
What is the quotient of twice the number and three
2X * 2X * 2X = 8X^3 2X^3 is saying 2*( X * X * X) = 2X^3
-2x = y^5 or y^5 = -2x y = (-2x)^(1/5)
y = 2x + 5 17 = 2x + 5 X = 6