Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
3x2 + 30x + 48 is a quadratic polynomial. If 3x2 + 30x + 48 = 0, then: 3(x + 2)(x + 8) = 0 ⇒ x + 2 = 0 → x = -2 or x + 8 = 0 → x = -8
3y plus 6x = 2
60x + 120x - 40x - 80x - 30x = 24030x = 240x = 240/3 = 80
With difficulty because it's not an equation but an expression.
x = 0.666666666666667 so 100 + (30x0.67) + (30x0.67) = around 180
-30x=6.3 x=-.21
Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
Factorising, we have, 9x2+ 30x + 25 = (3x + 5)2;thus, when y = 0, x = -1⅔. This tells us that the sole x-intercept of this function is at the vertex, (0, 1⅔).
3x2 + 30x + 48 is a quadratic polynomial. If 3x2 + 30x + 48 = 0, then: 3(x + 2)(x + 8) = 0 ⇒ x + 2 = 0 → x = -2 or x + 8 = 0 → x = -8
In the equation 30x=40, x is the number 30 is multiplied by in order to equal 40.
40%=30x .4=30x .4/30 = .01333333333333333333333333333333333333333333333333333333333333
x+x+2+x+4+x+6=42(x+x+x+x)+(2+4+6)=424x+12=424x=30x=15/2or 7 and 1/2
10x - 25 = 4x + 510x - 4x = 25 + 56x = 30x = 5
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?