Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
-30x=6.3 x=-.21
10x - 25 = 4x + 510x - 4x = 25 + 56x = 30x = 5
"Is" over "of" equals "%" over "100." 60/x=30/100 6000==30x 6000/30=x 200=x
For the equation: x5+7x3-30x=0 The highest exponent in the entire equation is 5 (from x5), so the equation is of degree 5.
Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
31x
Algebraically, with X = ' what. '30X = 180X = 180/30X = 6=====
Given ef is the midsegment of isosceles trapezoid abcd bc equals 17x ef equals 22.5x plus 9 and ad equals 30x plus 12 find ad?
56
3y plus 6x = 2
60x + 120x - 40x - 80x - 30x = 24030x = 240x = 240/3 = 80
30%=30/100 30/100x=21 100/1(30/100)x=100/1(21) 30x=2100 30x/30=2100/30 x=70
Solution :- 30X = 100. X = 100/30. X = 10/3. Finally answer is ten divided by three.
-30x=6.3 x=-.21