12 (twelve)
I assume the question should have said "subtract" and not "subtrack".
If the strict rules of BIDMAS or PIDMAS are applied then, since additions should be carried out before any subtractions,
3 + 1 + 3 - 2 + 2 + 5 = (3 + 1 + 3) - (2 + 2 + 5) = 7 - 9 = -2
However, most people treat + and - on par so that
3 + 1 + 3 - 2 + 2 + 5 = 12
3
1
+3
=7
-2
=5
+2
=7
+5
=12
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2
2==5 and 5!=3 or (5-2)^2>=1
There are 32 possible subset from the set {1, 2, 3, 4, 5}, ranging from 0 elements (the empty set) to 5 elements (the whole set): 0 elements: {} 1 element: {1}, {2}, {3}, {4}, {5} 2 elements: {1, 2}, {1, 3}, {1, 4}, {1, 5}, {2, 3}, {2, 4}, {2, 5}, {3, 4,}, {3, 5}, {4, 5} 3 elements: {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5} 4 elements: {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5} 5 elements: {1, 2, 3, 4, 5} The number of sets in each row above is each successive column from row 5 of Pascal's triangle. This can be calculated using the nCr formula where n = 5 and r is the number of elements (r = 0, 1, ..., 5). The total number of subset is given by the sum of row 5 of Pascal's triangle which is given by the formula 2^row, which is this case is 2^5 = 32.
It is Mathematically impossible. In order to find a single 7 in 1 1 1 1 2 1 1 1 3 1 2 2 2 2 3 2 2 2 The order would be as a requirement: 1 1 1 1 2 1 1 1 1 3 2 2 2 2 3 2 2 2 2 4 3 3 3 3 4 3 3 3 3 5 4 4 4 4 5 4 4 4 4 6 --- --- 5 5 5 5 6 5 5 5 5 7 (THERE!) If in that order the first 7 would be the 50th number. as from that you can see that the first 14 would be the 100th number, as well as the 21 being the 150th and so on.
(2/5) / (1/3) = (2/5)*(3/1) = 6/5 = 11/5
they are numbers. and if you add them together you get 11. if you muliply you get 24. if you subtrack you get 5. if you divide 8 by 3 you get 8/3 .
There are 64 subsets, and they are:{}, {A}, {1}, {2}, {3}, {4}, {5}, {A,1}, {A,2}, {A,3}, {A,4}, {A,5}, {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3, 5}, {4,5}, {A, 1, 2}, {A, 1, 3}, {A, 1, 4}, {A, 1, 5}, {A, 2, 3}, {A, 2, 4}, {A, 2, 5}, {A, 3, 4}, {A, 3, 5}, {A, 4, 5}, {1, 2, 3}, {1, 2, 4}, {1, 2, 5}, {1, 3, 4}, {1, 3, 5}, {1, 4, 5}, {2, 3, 4}, {2, 3, 5}, {2, 4, 5}, {3, 4, 5}, {A, 1, 2, 3}, {A, 1, 2, 4}, {A, 1, 2, 5}, {A, 1, 3, 4}, {A, 1, 3, 5}, {A, 1, 4, 5}, {A, 2, 3, 4}, {A, 2, 3, 5}, {A, 2, 4, 5}, {A, 3, 4, 5}, {1, 2, 3, 4}, {1, 2, 3, 5}, {1, 2, 4, 5}, {1, 3, 4, 5}, {2, 3, 4, 5}, {A, 1, 2, 3, 4}, {A, 1, 2, 3, 5}, {A, 1, 2, 4, 5}, {A, 1, 3, 4, 5}, {A, 2, 3, 4, 5}, {1, 2, 3, 4, 5} {A, 1, 2, 3,,4, 5} .
5/(√3 - 1)= 5(√3 + 1)/(√3 - 1)(√3 + 1)= (5√3 + 5)/[(√3)2 - 12)= (5√3 + 5)/(3 - 1)= 5√3 + 5)/2= 5√3/2 + 1/2
3 ÷ 2/5 = 3/1 ÷ 2/5 = 3/1 × 5/2 = (3×5)/(1×2) = 15/2 = 7½
(3 1/5) - (1 3/5) : If we borrow 1 from 3, then 3 1/5 becomes 2 6/5 [1 = 5/5, and 1/5+5/5 = 6/5]. Now can subtract 3/5 from 6/5, and subtract 1 from 2:6/5 - 3/5 = 3/5. 2-1 = 1. So the answer is 1 3/5.
2==5 and 5!=3 or (5-2)^2>=1
1 5/2 - 3/2 = (5-3)/2 = 2/2 = 1
Who: DixieLocation: Hotton, Desert IsleKeystrokes:1, 3, 2, 4, 3, 5, 4, 6, 5, 7, 6, 8, 8, 6,7, 5, 6, 4, 5, 3, 4, 2, 3, 1, 1Who: ElainaLocation: Wington, Bird IsleKeystrokes:3, 2, 1, 2, 3, 3, 3, 2, 2, 2, 3, 5, 5, 3,2, 1, 2, 3, 3, 3, 3, 2, 2, 3, 2, 1Who: HeinrichLocation: Chillton, Snow IsleKeystrokes:5, 3, 2, 1, 2, 3, 5, 3, 2, 1, 2, 3, 5, 3,5, 6, 3, 6, 5, 3, 2, 1Who: InaraLocation: Appleton, Horse IsleKeystrokes:3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 3, 2, 2,3, 3, 4, 5, 5, 4, 3, 2, 1, 1, 2, 3, 2, 1, 1Who: JasperLocation: Earton, Horse IsleKeystrokes:1, 2, 3, 4, 5, 6, 7, 8Who: KyleighLocation: Witherton, Rider IsleKeystrokes:3, 3, 5, 3, 2, 3, 1, 5, 5, 6, 5, 4, 5, 2, 8,7, 6, 5, 4, 3, 2, 5, 3, 2, 3, 1Who: SandraLocation: Flipperton, Dolphin IsleKeystrokes:1, 1, 2, 1, 2, 3, 2, 3, 4, 3, 4, 5, 4, 5, 6, 5,6, 7, 6, 7, 8, 5, 3, 1Who: SorenLocation: Crystalton, Ice IsleKeystrokes:3, 5, 3, 2, 1, 3, 5, 3, 2, 1, 2, 3, 4, 5,6, 5, 4, 3, 2Who: VeronicaLocation: Shellton, Turtle IsleKeystrokes:3, 2, 1, 3, 2, 1, 5, 4, 4, 3, 5, 4, 4, 3, 5, 8, 8,7, 6, 7, 8, 5, 5, 5, 8, 8, 7, 6,7 8, 5, 5, 4, 3, 2, 1Who: YancyLocation: Treeton, Horse IsleKeystrokes:1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1, 5, 5, 4, 4, 3, 3,2, 5, 5, 4, 4, 3, 3, 2, 1, 1, 5, 5, 6, 6, 5, 4, 4, 3, 3, 2, 2, 1
2: 1 and 2 3: 1 and 3 5: 1 and 5
1 2/3=5/3 (2/3)/(5/3)=(2/3)*(3/5)=2/5
The sample space is the following set: {(1. 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (2. 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3. 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (4. 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5. 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6), (6. 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)}
3 1/2