0
Add your answer:
Earn +20 pts
What is y7 divided by y4?
1.75
What is 1 divided by x divided by 2 divided by y?
0.5
What is y3?
y times y times y
(4x-y) plus (-10 plus y) if x3 and y4?
If x = 3 and y = 4 then the answer is 2
Can you solve for a b and c in the quadratic equation with only a list of data points?
Yes. You need at least three points with x and y coordinates for this. Let the points be: A(x1, y1), B(x2, y2) and C(x3, y3). For each of the points yi = ax2i + bxi + c, so you have to solve a set of simultaneous equations for i=1 ... 3(the y's and x's are no longer variables! the a, b, c are!): y1 = ax21 + bx1 + c, y2 = ax22 + bx2 + c, y3 = ax23 + bx3 + c
X4 plus y4 divided by x plus y?
(x4 + y4)/(x + y) = Quotient = x3 - x2y + xy2 - y3 Remainder = - 2y4/(x+y) So, x3 - x2y + xy2 - y3 - 2y4/(x+y)
How do you factor x to the sixth minus y to the sixth?
x6 - y6 = (x3)2 - (y3)2 = (x3 + y3) (x3 - y3) = (x + y)(x2 - xy + y2)(x - y)(x2 + xy + y2)
Factor completely x3-y3?
(x - y)(x^2 + xy + y^2
What is the answer to x plus y to 3rd power plus x minus y to 3rd power?
(x + y)3 + (x - y)3 = (x3 + 3x2y + 3xy2 + y3) + (x3 - 3x2y + 3xy2 - y3) = 2x3 + 6xy2 = 2x*(x2 + 3y2)
When can a polynomial is said to be sum or difference of two cubes?
When it is of the form x3 + y3 or x3 - y3. x or y can have coefficients that are perfect cubes, or even ratios of perfect cubes eg x3 + (8/27)y3.
How do you factor x3 - y3?
0
How do you factor x3 plus y3?
(x2 - xy + y2)(x + y)
How do you factor x3 plus y3 divide x plus y?
x^2 - xy + y^2
Six x squared divided by y times y cubed divided by twelve x to the fourth?
( 6x2 / y ) × ( y3 / 12x4) = 6x2y3 / 12x4y = y2 / 2x2
What is x3-y3-8?
You would need to know the value of either x or y, so that you could solve for the one independent variable.
If y equals 3 then y3 y3-y equals?
y3 x y3 - y (3)3 x 3(3) - 3 9 x 9 - 3 = ? 9 x 9= 81 81 - 3 = 78 I hope that solves your problem
How do you find a point which is equidistant from other three points?
For three points, (x1,y1), (x2,y2) & (x3,y3), you can set up 3 distance equations with variables x, y & z: z^2 = (x-x1)^2 + (y-y1)^2 z^2 = (x-x2)^2 + (y-y2)^2 z^2 = (x-x3)^2 + (y-y3)^2 3 equations and 3 variables....Solve away! z is your distance. x & y are the coordinates of the equidistant point.
