If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
4a + 3a = (4 + 3)a = 7a
3A + 9B = 3(A + 3B)
x^3 + ax + 3a + 3x^2 = (x^3 + 3x^2) + (ax + 3a) = x^2(x + 3) + a(x + 3) = (x + 3)(x^2 + a)
3a+ax+3b+bx = 3(a+b)+(a+b)x = (a+b)(3+x)
6a-3
If 3a+5=5a+3, then: 3a+5 - 3a = 5a+3 - 3a 5=2a+3 5 - 3=2a+3 - 3 2=2a a=1
"a" plus "3a" is equal to 4a. (3a+a=4a). You already have 3 "a's" and then you add another "a."
4a + 3a = (4 + 3)a = 7a
3A + 9B = 3(A + 3B)
x^3 + ax + 3a + 3x^2 = (x^3 + 3x^2) + (ax + 3a) = x^2(x + 3) + a(x + 3) = (x + 3)(x^2 + a)
13a - 6 + a = 5a + 3 + 3a 13a + a - 5a - 3a = 3 + 6 6a = 9 6a/6 = 9/6 a = 3/2
7a minus 2, if "3a-2" means 3a minus 2. 3a plus 1 and 1-3rd in parenthesis times 3a, if "3a-2" means 3a squared. a plus 3a squared plus 3a = 1-3rd times 3a plus 3a times 3a plus 1 times 3a = 3a plus 1 and 1-3rd in parenthesis times 3a
3a+ax+3b+bx = 3(a+b)+(a+b)x = (a+b)(3+x)
-8a + 3a = (-8 + 3)a = (5)a = 5a
This expression can be factored. ab + 3a + b2 + 3b = a(b + 3) + b(b + 3) = (a + b)(b + 3)
3(a+4) = 3a+12