3c+6=18
3c+6-6=18-6
3c=12
3c÷3=12÷3
c=4
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The solution (not sum) to the equation 21 = 3c + 6 is as follows:21 = 3c + 621 - 6 = 3c + 6 - 615 = 3c3c = 153c/3 = 21/3c = 7
Equality
3n+6=18 n+2=6 n=4
55
8d = 5d+18 8d-5d = 18 3d = 18 d = 6