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The solution (not sum) to the equation 21 = 3c + 6 is as follows:

21 = 3c + 6

21 - 6 = 3c + 6 - 6

15 = 3c

3c = 15

3c/3 = 21/3

c = 7

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Q: What is the sum of 21 equals 3c plus 6?

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4c+2 = 3c+9 4c-3c = 9-2 c = 7

17-3= 4c+3c c=2

3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4

That's not even a question. It's only a statement that says that some number is equal to itself.

a=2b 4b=6c becomes 2b=3c a=3c

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4c+2 = 3c+9 4c-3c = 9-2 c = 7

17-3= 4c+3c c=2

3c+6=18 3c+6-6=18-6 3c=12 3c÷3=12÷3 c=4

2b+3c

That's not even a question. It's only a statement that says that some number is equal to itself.

4 + 3c = 2c + 2Subtract 4 from each side:3c = 2c - 2Subtract 2c from each side:c = -2

If: 3c = 6Then: c = 2

Multiplying out the brackets it is: 7a+21-ac-3c

Doing it step by step:-7 = -3c + 933c = 7 + 933c = 100c= 33 1/3

a=2b 4b=6c becomes 2b=3c a=3c

2c + 4 - 3c = -9 + c + 5 -c + 4 = c - 4 -2c = -8 2c = 8 c = 4

If you mean 3c = 214, then c = 68

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