402
402
402.4286
402.4286
2 x 3 x 67 = 402 2 x 201 = 402 3 x 134 = 402 6 x 67 = 402 To solve such a problem you use prime decomposition: This allows you to break any integer down into a multiple of prime numbers as in 2x3x67=402. Two, Three and 67 are all prime. From there to find all possible options, multiply the primes together: 2x3x67=402 --> 3x67=201 --> 2x201=402 2x3x67=402 --> 2x67=134 --> 3x134=402 2x3x67=402 --> 2x3=6 --> 6x67=402 This is under the assumption that this problem is restricted to integers. If real numbers are used, there are infinitely many solutions:
402
402
67
8442 ÷ 21 = 402
100.5
23.6471
14.3571
8.375
0.005
29.35%
44.6667
52