2 x 3 x 67 = 402
2 x 201 = 402
3 x 134 = 402
6 x 67 = 402
To solve such a problem you use prime decomposition:
This allows you to break any integer down into a multiple of prime numbers as in 2x3x67=402. Two, Three and 67 are all prime. From there to find all possible options, multiply the primes together:
2x3x67=402 --> 3x67=201 --> 2x201=402
2x3x67=402 --> 2x67=134 --> 3x134=402
2x3x67=402 --> 2x3=6 --> 6x67=402
This is under the assumption that this problem is restricted to integers. If real numbers are used, there are infinitely many solutions:
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They know this because 3 is a factor of 402, therefore 3 multiplied by a number(134 to be precise) will give the quotinent 402 so 402 is therefore in the 3 times table.
There are an infinite amount of answers to that, such as: 402 + 66 = 468 459.5 + 8.5 = 468 233 + 235 = 468
Here is the 4 times table up to 12: 1 times 4 equals 4 2 times 4 equals 8 3 times 4 equals 12 4 times 4 equals 16 5 times 4 equals 20 6 times 4 equals 24 7 times 4 equals 28 8 times 4 equals 32 9 times 4 equals 36 10 times 4 equals 41 11 times 4 equals 44 12 times 4 equals 48
How about: 8*6*4 = 192
402 of them.