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What is the hypotenuse of a 40x50 rectangle?
A rectangle doesn't have a 'hypotenuse'. The diagonal of that one is 64.031 . (rounded)
How many square feet is 40x50?
If the given dimensions are in feet then 40 times 50 = 2,000 square feet
What is the total square foot of outside walls on a 2000 square foot home?
It depends on the height and shape of the building. Example: a 40x50 building with 10 foot walls = 1800 sq feet. 20x100 building with 15 foot walls 3600 sq feet
John and his wife needed their house painted. John wanted to hired Tom to paint the house. Tom estimated it would take 40 hours of labor at 50.00 per hour and 20 gallons of premium paint at 20.00?
The total cost is 40hrs x 50 dollars P the cost of the paint. I am guessing the paint is 20 dollars a gallon so we add 20x20. Then the total cost is 40x50+20x20=800+400=1,200 dollars.
45K equates to how much per hour?
Assuming there is a 40-hour work week and you work 50 weeks a year (maybe two weeks for vacation or being sick or whatever), multiply that together. 40x50=___. That is how many hours you will work in a year. To figure out how much money you will be making an hour with a $45,000 a year salary, divide 45,000 by the number of hours you will work in a year. $45,000 / # hours you will work in a year (the first math you did) = $___ per hour.
How do you calculate cubic square feet?
To calculate cubic square feet, you would multiply the length, width, and height measurements of the object or space in feet. The formula is: cubic feet = length (ft) x width (ft) x height (ft). This will give you the total volume in cubic feet.
What size resistor to use when replacing turn signal bulbs with led lights?
To make the flasher unit function properly, you need to put in a resistor that equals the resistance value of turn signal circuit. If the resistance is too low, then the turn signals will flash too slow, if at all. If the resistance is too high, then they will flash to fast.To find the total circuit resistance (if all the bulbs have the same resistance), you measure the OHM's value of a bulb and then divide the value by the number of bulbs in the circuit.Example: If you have 4 forty OHM bulbs, then the circuit resistance is 10 ohms.Another way of finding total resistance (if there are two bulbs with different resistance values) is to take the product of the values and divide it by the sum of the values,Example: 1 forty OHM bulbs and 1 Fifty OHM bulbs; 40X50= 2000 & 40+50= 90; 2000/90=22.22A third way to find total circuit resistance (if there are three or more bulbs that have different resistances) is to take the each resistance value, divided them by one, add them and divide the sum by one.Example: 1/ 1/r1+ 1/r2+ 1/r31/40= .025 & 1/50=.02; .025+.025+.02+.02=.09 & 1/.09=11.11 OHMs.
Can you give someexamples of real-life application of a quadratic function using x or y?
A very common application of a quadratic equation is using the Pythagorean Theorem. The application is posted at http://www.mathmotivation.com/science/quadratic-application.htmlAnother application of a quadratic equation used in higher math and engineering is where a second-order differential equation is solved for a spring-damper system. This sounds scary but actually has real-world application. This example also shows how the "imaginary" number "i" is used in a real-world application. This application is shown at http://www.mathmotivation.com/science/complex-numbers-application.htmlYou wanted the quadratic function (2 variables). Here goes. The free fall equation S = at2 + Vot + So. is used by anyone predicting the path of a projectile. During WWII I have read that the warships would actually have a mathematician on board to do the calculations when firing at enemy targets. This equation, and how it is derived is shown at http://www.mathmotivation.com/science/freefall.html I once used this equation to calculate the depth of a canyon - I threw a rock straight out, counted the seconds, and was able to use the simplified version S = 16t2 to calculate the depth. Actually, the "canyon" was the bottom side of a dam on a river - my calculated depth gave me the depth of the lake on the dammed up side.
