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What is the hypotenuse of a 40 x 60 rectangle?
By splitting the rectangle into half diagonally, we obtain two right triangles with sides 40 and 60. Using Pythagorean theorem, we obtain approximately 72.11 as the hypotenuse of both of them.
Diagonal measurement of a rectangal?
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
Area of a rectangle using diagonal and height?
Use the Pythagorean Theorem (a2 + b2 = c2, where a and b are the legs and c is the hypotenuse) and then you will know the base of the rectangle (which would be a or b, depending on which you use). Then you can multiply the base and height to find the area of the rectangle!Great answer!
What is the length of the hypotenuse of a right triangle that has a base of 5 inches and a height 12 inches?
Hypotenuse^2 = base^2 + height^2, substitute the given values Hypotenuse^2 = 5^2 + 12^2 Hypotenuse^2 = 25 + 144 Hypotenuse^2 = 169 Hypotenuse = √169 Hypotenuse = 13 Thus, the hypotenuse is 13 inches.
If abce is an isosceles trapezoid and acde is a rectangle what is the length of ae when ab equals 10 and ec equals 20?
Draw the isosceles trapezoid ABCE, where the length of the bases AB (on the top) and EC are respectively 10 and 20. From A and B draw the perpendiculars to the base EC of the trapezoid, and label the point of intersections with F and G). The rectangle ABGF is formed, where the length of FG is 10 (since the two opposite sides of a rectangle are congruent). Then the lengths of EF and GC are 5 (since the trapezoid is isosceles). Draw the diagonal AC. From C and E draw the parallel lines respectively to AE and AC, and label the intersection point with D. So the rectangle ACDE is formed. Thus, the triangle EAC is a right triangle, where the angle A is 90 degrees (as the angle of a rectangle), and AF is the altitude drawn at the hypotenuse EC. We have a theorem that states: "If an altitude is drawn to the hypotenuse of a right triangle, then each leg is the geometric mean between the hypotenuse and its touching segment on the hypotenuse". So we have, EC/AE = AE/EF, which yields AE2 = EC*EF, and so AE = √(20*5) = 10. or using the same diagram, Since the diagonals of a rectangle bisect each other (let's say they bisect at H), then AH is the median of the right triangle EAC, drawn to the hypotenuse EC, so its length is the half of the hypotenuse. So the length of AH is 10. Since the trapezoid is isosceles, then the diagonal BE also will form a right triangle EBC, where the median BH also it is 10. So the triangle ABH is equilateral, where angle A is 60 degrees, and it is congruent with angle H of the triangle AHE, as two alternate interior angles. Thus, the isosceles triangle AHE is also equilateral, where AE = 10.
Can a triangle tesellate to form a rectangle?
Two right-angled triangles placed hypotenuse to hypotenuse with one inverted form a rectangle...
What is the hypotenuse of a 50 x 60 rectangle?
A rectangle doesn't have a hypotenuse.The diagonal of this one is sqrt(6,100) = 78.1025 (rounded)
What is the hypotenuse of a 40 x 60 rectangle?
By splitting the rectangle into half diagonally, we obtain two right triangles with sides 40 and 60. Using Pythagorean theorem, we obtain approximately 72.11 as the hypotenuse of both of them.
What is the hypotenuse of a 6 x 40 rectangle?
Half of a rectangle is a right angled triangle. Pythagoras! Hyp squared = 6 squared + 40 squared = 36 + 1600 = 1696 so Hypotenuse = sqrt 1696 = 41.18252
How do you find the width and length of a rectangle knowing ONLY the diagonal and its angle?
By using the trigonometric ratios of Sine and Cosine. The diagonal forms the hypotenuse of a right angled triangle with the length and width of the rectangle forming the other two sides of the triangle - the adjacent and opposite sides to the angle. Then: sine = opposite/hypotenuse → opposite = hypotenuse x sine(angle) cosine = adjacent/hypotenuse → adjacent = hypotenuse x cosine(angle)
Can you make a rectangle out of two triangles and a square?
Sure, place a triangle's hypotenuse (longest side) on the other triangle's hypotenuse, that will give either a square or a rectangle. Then place the square on one end of the rectangle. For this to work though, the length of the square's side HAS to equal the length of the triangles hypotenuses, and likewise each triangle's hypotenuse much equal the length of a side of the square. Hope this is clear.
What is 40x50?
40 x 50 = 2000
How do you make a rectangle with four triangles?
To create a rectangle using four triangles, you can arrange two pairs of congruent right triangles. Each pair should be positioned so that the hypotenuse of one triangle aligns with the hypotenuse of the other, forming two opposite corners of the rectangle. By placing one pair of triangles on the top and the other on the bottom, the right angles will meet at the corners, effectively outlining a rectangle.
Diagonal measurement of a rectangal?
The diagonal of a rectangle is measured by using Pythagores theorem if you have the length and breadth of the rectangle. Say the length is 4cm and breadth is 3cm then the diagonal(hypotenuse) would be 42 + 32 =16 + 9= 25 = 52. Hence the hypotenuse or the diagonal is 5cm. Is that fine? Have a good day.
How do you make a parallelogram that is not a square from 4 identical isosceles right triangles?
Two isosceles right triangles, if joined hypotenuse-to-hypotenuse will make a square. Two squares, sided by side, make a rectangle which is a parallelogram, and not a square.
What is the area of a right-angle triangle with a 3 base 4 height and 5 hypotenuse?
Hmmm. the triangle you describe is HALF of a rectangle...
What is the diagonal distance of a rectangle 84 inches wide by 85.5 inches long?
120 inches (by finding the hypotenuse of a right triangle).
